我想做一个模拟器，你可以进入房间然后离开。如果你离开了，你就在房间里，然后才进来。我想用递归和调用堆栈来实现它。如果我去一个新房间，效果会很好，但我不能回去了。有什么解决办法吗？

import java.util.Scanner;

public class Hausaufgabe10Aufgabe01 {

    public static void main(String[] args) {
        Room workingroom = new Room("Arbeitszimmer", false);
        Room bedroom = new Room("Schlafzimmer", false);
        Kitchen kitchen = new Kitchen("Kueche", false, false);
        Bathroom bathroom = new Bathroom("Badezimmer", false, false);
        Room hall = new Room("Flur", false);
        hall.setNeighborRooms(bathroom, kitchen, bedroom, workingroom);
        workingroom.setNeighborRooms(bedroom);
        bedroom.setNeighborRooms(workingroom);
        Flat myFlat = new Flat(bathroom, kitchen, bedroom, workingroom, hall);
        boolean inFlat = false;
        Scanner input = new Scanner(System.in);
        walkThrough(myFlat, hall, input);
    }

    public static void walkThrough(Flat myFlat, Room myRoom, Scanner input) {
        while (true) {

            System.out.println("\nSie sind im: " + myRoom.getName());
            System.out.println("Was wollen sie tun ? ");

            System.out.println("1) Lichtsschalter bestätigen ? ");
            System.out.println("2) Raum verlassen? ");
            System.out.println("3) Nachbar Raum betreten ? ");

            int intMax = 3;
            if (myRoom.getName().equals("Kueche")) {
                System.out.println("4) Herd betätigen ? ");
                intMax = 4;
            }
            if (myRoom.getName().equals("Badezimmer")) {
                System.out.println("4) Dusche betätigen ? ");
                intMax = 4;
            }

            boolean shouldIReturn = false;
            int choosenNumber = input.nextInt();
            switch (choosenNumber) {

            case 1:
                myRoom.useLight();
                break;
            case 2:
                shouldIReturn = true;
                break;
            case 3:
                if (myRoom.getNeighborRooms() != null) {
                    myRoom = chooseRoom(input, myRoom);
                    walkThrough(myFlat, myRoom, input);
                } else {
                    System.out.println("Keine Nachbarraum vorhanden");
                }
                break;
            case 4:
                if (intMax == 4) {
                    myRoom.useSpecial();
                }
                break;
            default:
                System.out.println("\nGeben sie eine richtige Eingabe ein!!");
                if(intMax < 4) {
                    System.out.println("1 - 3 \n");
                } else {
                    System.out.println("1 - 4 \n");
                }
                break;
            }

            if (shouldIReturn) {
                return;
            }
        }
    }

    public static Room chooseRoom(Scanner input, Room myRoom) {
        if (myRoom.getNeighborRooms().length > 0) {
            for (int i = 0; i < myRoom.getNeighborRooms().length; ++i) {
                System.out.println((i + 1) + ") "
                        + myRoom.getNeighborRooms()[i].getName());
            }
            int choosenRoom = input.nextInt() - 1;
            return myRoom.getNeighborRooms()[choosenRoom];
        }
        return myRoom.getNeighborRooms()[0];
    }
}

我试图返回，所以我结束了当前的功能并返回到以前的功能，但我不知道我以前所在的房间的名称。我怎样才能得到我以前的东西？