我遇到了一种情况，我必须支持现有的客户机，他们使用的RESTAPI负载低于有效负载，

{
  "firstName": "First name",
  "secondName": "Second name",
  "dateOfBirth": "01/12/2020",
  "profession": "Software Developer",
  "salary": 0,

**"value": "value1"**

}

但现在根据需要，他们可以为值字段发送数组，如下所示：

{
  "firstName": "First name",
  "secondName": "Second name",
  "dateOfBirth": "01/12/2020",
  "profession": "Software Developer",
  "salary": 0,

**"value": ["Value1", "value2", "Value3"]**

}

现有代码使用 @RequestBody 将其转换为 PersonDTO person ，该类还包含一个名为 isMutliValue() & getMultiValueFor() ，这些方法基于逗号拆分字符串，然后决定并返回其中的值。但是现在对于这个需求，我必须做一个修改，以检查客户机是以值还是简单字符串形式发送数组。如果它是一个简单的字符串，那么不要基于逗号拆分它，只需处理它，但是如果它是一个数组，则从中取出值并发送单个值。

public class PersonDTO {
    private String firstName;
    private String secondName;
    // Formats output date when this DTO is passed through JSON
    @JsonFormat(pattern = "dd/MM/yyyy")
    // Allows dd/MM/yyyy date to be passed into GET request in JSON
    @DateTimeFormat(pattern = "dd/MM/yyyy")
    private Date dateOfBirth;

    private String profession;
    private BigDecimal salary;
    private String value;

    public PersonDTO(
            String firstName, String secondName, Date dateOfBirth, String profession, BigDecimal salary, String value) {
        this.firstName = firstName;
        this.secondName = secondName;
        this.dateOfBirth = dateOfBirth;
        this.profession = profession;
        this.salary = salary;
        this.value = value;
    }

    public PersonDTO() {}

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    public String getSecondName() {
        return secondName;
    }

    public void setSecondName(String secondName) {
        this.secondName = secondName;
    }

    public Date getDateOfBirth() {
        return dateOfBirth;
    }

    public void setDateOfBirth(Date dateOfBirth) {
        this.dateOfBirth = dateOfBirth;
    }

    public String getProfession() {
        return profession;
    }

    public void setProfession(String profession) {
        this.profession = profession;
    }

    public BigDecimal getSalary() {
        return salary;
    }

    public void setSalary(BigDecimal salary) {
        this.salary = salary;
    }

    public Object getValue() {
        return value;
    }

    public void setValue(Object value) {
        this.value = value;
    }

    public boolean isMultiValued() {
        return value.split(",").length > 1;
    }

    public String[] getMultiValues() {
        return value.split(",");
    }
    public String toString(){
        return "FirstName : " + firstName +" SecondName : "+ secondName +", Value : "+ value.toString();
    }

}

请帮助我，我们如何在json负载的单个字段中处理不同类型的值。