我有一些代码可以在javascript ide中很好地工作,比如webstorm,但是当我尝试使用nashorn库(在java程序中运行js)将其移植到java时,会出现以下错误:“name:undefined,age:undefined”(根据这里的错误,可能还会有其他代码跟随)
下面是完整的代码。下面的这种编码方法似乎在一般情况下是有效的,但是在有些情况下,我并没有得到预期的结果。
如有任何帮助或建议,我们将不胜感激。
谢谢!
public class JavaScriptEvaluationExample
{
public static void main(String[] args) throws ScriptException, NoSuchMethodException
{
// Basic JavaScript evaluation
String json = "{\n" +
" \"name\": \"John\",\n" +
" \"age\": 30,\n" +
" \"cars\": [\n" +
" {\n" +
" \"name\": \"Ford\",\n" +
" \"models\": [\n" +
" \"Fiesta\",\n" +
" \"Focus\",\n" +
" \"Mustang\"\n" +
" ]\n" +
" },\n" +
" {\n" +
" \"name\": \"BMW\",\n" +
" \"models\": [\n" +
" \"320\",\n" +
" \"X3\",\n" +
" \"X5\"\n" +
" ]\n" +
" },\n" +
" {\n" +
" \"name\": \"Fiat\",\n" +
" \"models\": [\n" +
" \"500\",\n" +
" \"Panda\"\n" +
" ]\n" +
" }\n" +
" ]\n" +
"}";
String jsScript = "function parseJSONFields(param)\n" +
"{\n" +
" var result = \"\";\n" +
" var carName =\"\" ;\n" +
" var models = \"\";\n" +
" var name = param.name + \",\";\n" +
" var age = param.age;\n" +
" result = \"Name: \" + name + \" Age: \" + age + \"\\n\";\n" +
" for (item in param.cars)\n" +
" {\n" +
" result += \" \"+ \" >> \" + param.cars[item].name +\": \"\n" +
" result+= \" \" + param.cars[item].models\n" +
" result += \"\\n\";\n" +
" }\n" +
" return result;\n" +
"}";
System.out.println(runJS("parseJSONFields", json, jsScript));
}
// ------------------------------------------------------------------------------------------------
private static Object runJS(String functionName, String param, String script) throws ScriptException, NoSuchMethodException
// ------------------------------------------------------------------------------------------------
{
Object resultString = "";
String errorResultString = "";
ScriptEngine js = null;
try
{
if (param.length() > 0)
{
js = new ScriptEngineManager().getEngineByName("javascript");
js.eval(script);
Invocable inv = (Invocable) js;
}
}
catch (Exception e)
{
errorResultString = e.getMessage() + " ---> " + e.getMessage();
}
return errorResultString.length() > 0 ? errorResultString
: ((Invocable) js).invokeFunction(functionName, param);
}
}
1条答案
按热度按时间hrysbysz1#
感谢所有回复的人。
问题是,正如第一个人所指出的,我忘记了用json.parse()语句将字符串转换为json对象。
再次非常感谢。