如何解决一个不兼容的类型:用数组返回java中的错误?

nfeuvbwi  于 2021-07-07  发布在  Java
关注(0)|答案(2)|浏览(461)

这是我未完成的代码。我在phonebook类中有数组,main正在调用一个方法来打印数组中的所有内容,但是出现了一个错误。
主要类别:

import java.util.Scanner;
public class Main {
  public static void main(String[] args) {

    Scanner myObj = new Scanner(System.in);
    System.out.println("What would you like to do: \n 1) ADD to phone book \n 2) DELETE from phone book \n 3) CALL \n 4) PRINT phone book \n 5) quit");
    int input = myObj.nextInt();

    //constructor scanner inputs
    String ISpeedDial = myObj.nextLine();
    String Iname = myObj.nextLine();
    String Inumber = myObj.nextLine();
    //constructor
    PhoneBook b1 = new PhoneBook(ISpeedDial, Iname, Inumber);

    if (input == 1) {//add contact
// scanner saying what is the name of your new contact? what is the # of you new contact? Would you like this contact to be on your spead dails. 
//ptints your new contat is:____ and their # is ___-___-____ and the your Spead dial number is_

    }
    else if (input == 2) {//delete contact
// 
    }
    else if (input == 3) {//make call(from contact or not?)

    }
    else if (input == 4) {//print phone book
    b1.print();
    System.out.println(b1.print() + " ");
    //System.out.print(SD0[i] + " ");
    //t1.Right();//gets right triangle t/f
    //System.out.println("It is a right triangle: " + t1.Right());

    }
    else if (input == 5) {//quit
      return;
    }
    else {//invalid number
      System.out.println("invalid input: " + input);
      return;
    }

  }
}

电话簿类:

public class PhoneBook {

  //instance variables
  private String SpeedDial;
  private String name;
  private String number;

//Account constructor
public PhoneBook(String MSpeedDial, String Mname, String Mnumber){

SpeedDial = MSpeedDial;
name = Mname;
number = Mnumber;
}

//arrays
  String [] SD0 = new String[3];
  String [] SD1 = new String[3];
  String [] SD2 = new String[3];
  String [] SD3 = new String[3];
  String [] SD4 = new String[3];
  String [] SD5 = new String[3];
  String [] SD6 = new String[3];
  String [] SD7 = new String[3];
  String [] SD8 = new String[3];
  String [] SD9 = new String[3];

//method to deposit a specified amount into the account
public void add(){

  SD0[0] = "0";
  SD0[1] = "jo";
  SD0[2] = "123";

}

public void delete(){

}
//getter method to return balance
//named without void because it will return a value unlike the ones above
public String print(){
  for (int i = 0; i < SD0.length; i++) {  
    return SD0[i];  
  }
  for (int i = 0; i < SD1.length; i++) {  
    return SD1[i];  
  }
  for (int i = 0; i < SD2.length; i++) {  
    return SD2[i];  
  }
  for (int i = 0; i < SD3.length; i++) {  
    return SD3[i];
  }
  for (int i = 0; i < SD4.length; i++) {  
    return SD4[i];  
  }
  for (int i = 0; i < SD5.length; i++) {  
    return SD5[i];  
  }
  for (int i = 0; i < SD6.length; i++) {  
    return SD6[i];  
  }
  for (int i = 0; i < SD7.length; i++) {  
    return SD7[i]; 
  }
  for (int i = 0; i < SD8.length; i++) {  
    return SD8[i];  
  }
  for (int i = 0; i < SD9.length; i++) {  
    return SD9[i];  
  } 
  return;
}

}

我的错误是:

PhoneBook.java:76: error: incompatible types: missing return value
  return;

有人知道如何解决这个问题吗?
另外,有没有一种方法可以缩短phone book类中的行(46-75),即打印每个数组的for循环?
谢谢您!

qnyhuwrf

qnyhuwrf1#

return语句立即返回。它不是在建一根绳子。所以只要sd0的长度大于0,代码就会返回sd0[0]。
错误是没有任何参数的最终返回。return“”将修复编译错误,但它可能不是您真正想要的。

vngu2lb8

vngu2lb82#

print方法中的最后一个返回值不返回任何内容,但需要字符串:

...
  for (int i = 0; i < SD9.length; i++) {  
    return SD9[i];  
  } 
  return;

你可以考虑使用 String [][] SD = new String[10][3]; 而不是拥有 SDx 作为变量

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