为什么rmi代码抛出accesscontrolexception?

zf2sa74q  于 2021-07-07  发布在  Java
关注(0)|答案(1)|浏览(448)

我有一个java类,其中rmi代码编写为:

  1. public class Test{
  2. public static void main(String[] args){
  3. System.setProperty("java.security.policy","file:/C:/myFloder/server.policy");
  4. if (System.getSecurityManager() == null) {
  5. System.setSecurityManager(new SecurityManager());
  6. log.info("Security manager installed.");
  7. } else {
  8. log.info("Security manager already exists.");
  9. }
  10. try {
  11. LocateRegistry.createRegistry(1099);
  12. log.info("java RMI registry created.");
  13. } catch (RemoteException e) {
  14. log.info("java RMI registry already exists.");
  15. }
  16. Naming.unbind("//" + serverIp + ":1099/ServletPath");
  17. log.info("RMI stareted successfully...!!");
  18. }
  19. }

以下是服务器策略:

  1. grant {
  2. permission java.security.AllPermission;
  3. };

但当我试图执行它时,它总是给我同样的异常。我也尝试过stackoverflow的各种解决方案,但都是徒劳的。

  1. java.security.AccessControlException: access denied ("java.net.SocketPermission" "127.0.0.1:1099" "connect,resolve")
  2. at java.security.AccessControlContext.checkPermission(AccessControlContext.java:472)
  3. at java.security.AccessController.checkPermission(AccessController.java:884)
  4. at java.lang.SecurityManager.checkPermission(SecurityManager.java:549)
  5. at java.lang.SecurityManager.checkConnect(SecurityManager.java:1051)
  6. at java.net.Socket.connect(Socket.java:584)
  7. at java.net.Socket.connect(Socket.java:538)
  8. at java.net.Socket.<init>(Socket.java:434)
  9. at java.net.Socket.<init>(Socket.java:211)
  10. at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(RMIDirectSocketFactory.java:40)
  11. at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(RMIMasterSocketFactory.java:148)
  12. at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:613)
  13. at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:216)
  14. at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:202)
  15. at sun.rmi.server.UnicastRef.newCall(UnicastRef.java:342)
  16. at sun.rmi.registry.RegistryImpl_Stub.rebind(Unknown Source)
  17. at java.rmi.Naming.rebind(Naming.java:177)
  18. at com.ist.ivision.rmi.server.SendOnQueueImpl.initMethod(SendOnQueueImpl.java:99)
  19. at com.ist.ivision.rmi.server.SendOnQueueImpl.main(SendOnQueueImpl.java:143)
  20. at com.ist.ivision.servlet.IVisionStartup$2.run(IVisionStartup.java:124)
  21. at java.lang.Thread.run(Thread.java:745)
  22. java.security.AccessControlException: access denied ("java.io.FilePermission" "filepath/A.java" "write")
  23. at java.security.AccessControlContext.checkPermission(AccessControlContext.java:472)
  24. at java.security.AccessController.checkPermission(AccessController.java:884)
  25. at java.lang.SecurityManager.checkPermission(SecurityManager.java:549)
  26. at java.lang.SecurityManager.checkWrite(SecurityManager.java:979)
  27. at java.io.FileOutputStream.<init>(FileOutputStream.java:200)
  28. at java.io.FileOutputStream.<init>(FileOutputStream.java:101)
  29. at java.io.FileWriter.<init>(FileWriter.java:63)

有人能告诉我我做错了什么吗??
谢谢

wj8zmpe1

wj8zmpe11#

查看现有的java.policy文件,格式看起来也不同。
//默认情况下,标准扩展获得所有权限

  1. grant codeBase "file:${{java.ext.dirs}}/*" {
  2. permission java.security.AllPermission;
  3. };

我还要再次检查自定义.policy文件的路径是否正确。
一个有用的stackoverflow是:javarmi accesscontrolexception:access denied
=======已编辑
否则,请尝试从代码中删除system.setproperty(),并在运行时将自定义策略文件作为ide的运行时参数指向:
删除system.setproperty()
修改eclipse/intellij并添加运行时参数
-djava.security.manager-djava.security.policy=c:/myfloder/server.policy
=============编辑2
尝试这样做,而不是使用文件:

  1. Policy.setPolicy(new Policy() {
  2. @Override
  3. public boolean implies(ProtectionDomain domain, Permission permission) {
  4. return true; // all permissions
  5. }
  6. });
  7. System.setSecurityManager(new SecurityManager());
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