我编写了一个java程序来获取文件的行，并整理出一个特定的id，然后将其从十六进制转换为ascii字符。在找到“0d”十六进制字符之前，它对几个文件都很有用，似乎是回车符（不知道这是怎么回事）。
当它遇到这种情况时，它将结束行输出（它不应该这样做）。我搞不清楚发生了什么事。
这是代码，编译时没有错误。我附上了一张结果照片。

文件1包含在id之前的字符=:lenght=8 在那之后需要转换8个十六进制字符。之后，程序转换并在同一行中添加文本。我需要他们站在同一条线上找出规律。

import java.io.*;
import java.util.Scanner;
import java.io.FileWriter;
import java.io.IOException;
public class FrameDecoder {
    public static void main(String[] args) throws IOException {
        try {
            // Sortam frameurile cu id-ul tinta
            File fisierSursa = new File("file1.txt"); //Fisierul original
            FileWriter fisierData = new FileWriter("file2.txt");  //Fisierul cu frameurile care au id-ul cautat
            FileWriter fisierTranzit = new FileWriter("file3.txt");  //Fisier cu caractere HEX, care va fi sters.
            Scanner citireSursa = new Scanner(fisierSursa);
            while (citireSursa.hasNextLine()){
                String data = citireSursa.nextLine();
                //System.out.println("data = " + data);
                int intIndex = data.indexOf("ID=289");  // idul pe care il cauti
                int intIndex2 = data.indexOf("ID=1313");  //al doilea id pe care il cauti
                if (intIndex != -1 || intIndex2 != -1){
                    char[] text = data.toCharArray();
                    int counter = 0;
                    for (int i=0; i<text.length; i++){
                        if (text[i] == ':' && counter < 5){
                            counter++;
                        }
                        if (text[i] == ':' && counter == 5){
                            fisierTranzit.write(text[i+1]);
                            fisierTranzit.write(text[i+2]);
                        }
                    }
                    fisierTranzit.write("\r\n");
                    fisierData.write(data + "\r\n");
                }
            }
            citireSursa.close();
            fisierTranzit.close();
            fisierData.close();
            // Convertire HEX to ASCII
            FileWriter fisierAscii = new FileWriter("file4.txt");  //Fisier care va contine caraterele ASCII decodate
            File fisierTranzitRedeschis = new File("file3.txt");  //Reinitializam fisierul tranzit pentru a putea citi din el
            Scanner citireTranzit = new Scanner(fisierTranzitRedeschis);
            while (citireTranzit.hasNextLine()){
                String data2 = citireTranzit.nextLine();
                System.out.println("data2 = " + data2);
                if (data2.length() % 2 != 0){
                    System.err.println("Invalid hex string!");
                    return;
                }
                StringBuilder builder = new StringBuilder();
                for (int i=0; i<data2.length(); i=i+2){
                    //Impartim sirul in grupe de cate doua caractere
                    String s = data2.substring(i, i+2);
                    //Convertim fiecare grup in integer folosinf valueOfTheMetod
                    int n = Integer.valueOf(s, 16);
                    //Convertim valoare integer in char
                    builder.append((char)n);
                }
                fisierAscii.write(builder.toString() + "\r\n");
                //System.out.println(builder.toString());
            }
            citireTranzit.close();
            fisierAscii.close();
            //Stergem fisierul 3
            File stergereFisier3 = new File("file3.txt");
            if(stergereFisier3.delete()){
                System.out.println("File 3 deleted successfully");
            }else{
                System.out.println("Failed to delete file 3");
            }
            // Combinam fisierele
            PrintWriter fisierFinal = new PrintWriter("file5.txt");
            BufferedReader br1 = new BufferedReader(new FileReader("file2.txt"));
            BufferedReader br2 = new BufferedReader(new FileReader("file4.txt"));
            String line1 = br1.readLine();
            String line2 = br2.readLine();
             //loop to copy lines
             //of file1.txt and file2.txt
             //to file3.txt alternatively
            while (line1 != null || line2 !=null){
                if(line1 != null){
                    fisierFinal.print(line1 + "  ");
                    line1 = br1.readLine();
                }
                if (line2 != null){
                    fisierFinal.println(line2 );
                    line2 = br2.readLine();
                }
            }
            fisierFinal.flush();
            //closing resources
            br1.close();
            br2.close();
            fisierFinal.close();
            System.out.println("Merged files succesfully");
            //Stergem fisierul 2 si 4
            File stergereFisier2 = new File("file2.txt");
            File stergereFisier4 = new File("file4.txt");
            if(stergereFisier2.delete() && stergereFisier4.delete()){
                System.out.println("Files 2 and 4 deleted successfully");
            }else{
                System.out.println("Failed to delete files 2 and 4");
            }
        }catch (FileNotFoundException e){
            System.out.println("An error occurred.");
            e.printStackTrace();
        }catch (IOException e){
            System.out.println("No data to print");
            e.printStackTrace();
        }
    }
}

编辑：我作弊了一点，在打印十六进制字符时设置了一个条件，如果遇到0d，就用00替换。成功了。我也会试试你的方法，那一种似乎比我的好。

for (int i=0; i<text.length; i++){
                        if (text[i] == ':' && counter < 5){
                            counter++;
                        }
                        if (text[i] == ':' && counter == 5){
                            if(text[i+1] == '0' && text[i+2] == 'D'){
                                fisierTranzit.write('0');
                                fisierTranzit.write('0');
                            }
                            else{
                                fisierTranzit.write(text[i+1]);
                                fisierTranzit.write(text[i+2]);
                            }
                        }
                    }