我注解了我的代码，以帮助您理解我的逻辑，我基本上收到一个边值，我必须画一个三角形使用x的视觉显示其周长(各方都是平等的）
因此，在创建将填充包含图形的矩阵的单个数组时，随着迭代的继续，一些赋值会丢失，只保留最后一次迭代的值，并用这些值填充整个矩阵，这使我失去了所有的前一行，组成一个漂亮的三角形绘图，我无法打印成一个txt文件(我可以通过在循环中打印来在控制台中打印它，因为它生成了对应于一条绘图线的每个数组，但这只是一个暂时的幻觉，因为我没有将矩阵和x保持在适当的位置）。
如果有人能帮我不失去这个价值，并且能把它储存起来，我会很高兴的。
注意：父类figura只提供一个名为lado的int。

public class Triangulo extends Figura {
    char[] lineaI;
    char[] lineaT;
    char[][] matT;
    public char[][] matDibujo(int lado) {
        this.linea = new char[(lado+lado-1)]; //side int value to determine an eq. triangle base length
        lineaI = new char[linea.length]; //multiple intermediate single arrays that fill triangle diagonally
        lineaT = new char[linea.length]; //triangle base array
        matT = new char[lado][linea.length]; // matrix containing {{},{},{},{}} n individual arrays representing a row in the drawing (top to bottom)
        //Create triangle base line array 
        for (int i = 0; i < linea.length; i++) {
            if (i == 0 ) {
                linea[i] = 'X';
            } else if (i%2 == 0) {
                linea[i] = 'X';
            } else {
                linea[i] = ' ';
            }
            //Create triangle top point array
            if (i == (lado-1)) {
                lineaT[i] = 'X'; 
            } else {
                lineaT[i] = ' ';
            }
        }
        //Fill matrix with first array (top axis)
        matT[0] = lineaT;
        //Fill matrix last array (triangle base) 
        matT[lado-1] = linea;
        //System.out.println(matT[lado-1]);
        //THIS IS THE LOOP NOT SAVING CORRESPONDING lineaI full single array to matT[j], 
        //instead it's replacing every matT[j] with the last value of lineaI.
        //Create multiple arrays to fill n-sided triangle from top axis to base diagonally (parting from top axis)  
        for (int j = 1; j < (lado-1); j++) {
            for (int i = 0; i < linea.length; i++) {
                if (i == (lado-1-j) ) {
                    lineaI[i] = 'X';
                } else if (i == (lado-1+j) ) {
                    lineaI[i] = 'X';
                } else {
                    lineaI[i] = ' ';
                }
            }
            matT[j] = lineaI;
        }
        //return the matrix so we can print it
        return matT;
    }
    //Dibujar en txt
    public void dibuja(char[][] matriz) {
        for (int i = 0; i < matriz.length; i++) {
            System.out.println(matriz[i]);      
        }
    }
    public static void main(String[] args) {
        char[][] mat;
        Triangulo t = new Triangulo();
        mat = t.matDibujo(4);
        t.dibuja(mat);
        //This is the outcome, since we lost matT[1] and got it replaced by the last lineaI contents, which should
        //only belong to matT[2]
        /*      X                     The outcome should be             X                       
              X   X                                                    X X     ---> this line is lost and
              X   X                                                   X   X    ----> replaced by this one
             X X X X                                                 X X X X                                   */
    }
}