休眠4.3.11
在hibernate中保存以下对象图时遇到问题。正在使用merge()方法保存雇主。
Employer
|_ List<EmployerProducts> employerProductsList;
|_ List<EmployerProductsPlan> employerProductsPlan;
雇主和雇员产品有一个自动生成的pk。employerproductsplan是一个复合键,由employerproducts id和带有计划代码的字符串组成。
当employerproducts列表中有一个临时对象级联到 List<EmployerProductsPlan>
. 我一直试图克服的第一个错误是一个内部休眠npe。这里的这篇文章完美地描述了我遇到的一个问题,当使用@embeddeble和cascade持久化三个级别时,导致空指针在插入的id上休眠空指针
op留下了一条注解,指定了他们要解决的问题,但是当我更改为建议的Map时,我最终会遇到一个不同的错误。更改Map后,我现在得到
org.hibernate.NonUniqueObjectException: A different object with the same identifier value was already associated with the session : [com.webexchange.model.EmployerProductsPlan#com.webexchange.model.EmployerProductsPlanId@c733f9bd]
由于其他库依赖关系,我现在无法升级到4.3.x以上。这个项目使用的是springbootstarter数据jpa1.3.3。除了调用merge()并传递employer对象之外,没有其他工作在会话上执行。
下面是每个类的Map:
雇主
@Entity
@Table(name = "employer")
@lombok.Getter
@lombok.Setter
@lombok.EqualsAndHashCode(of = {"employerNo"})
public class Employer implements java.io.Serializable {
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "EMPLOYER_NO", unique = true, nullable = false)
private Long employerNo;
.....
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "employer", orphanRemoval = true)
private List<EmployerProducts> employerProductsList = new ArrayList<>(0);
}
员工产品
@Entity
@Table(name = "employer_products")
@Accessors(chain = true) // has to come before @Getter and @Setter
@lombok.Getter
@lombok.Setter
@lombok.EqualsAndHashCode(of = {"employerProductsNo"})
public class EmployerProducts implements Serializable {
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "employer_products_no", unique = true, nullable = false)
private Long employerProductsNo;
@ManyToOne
@JoinColumn(name = "employer_no", nullable = false)
private Employer employer;
......
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "employerProducts", orphanRemoval = true)
private List<EmployerProductsPlan> employerProductsPlanList = new ArrayList<>(0);
}
员工产品计划
@Accessors(chain = true) // has to come before @Getter and @Setter
@lombok.Getter
@lombok.Setter
@lombok.EqualsAndHashCode(of = {"id"})
@Entity
@Table(name="employer_products_plan")
public class EmployerProductsPlan implements Serializable {
@EmbeddedId
@AttributeOverrides({ @AttributeOverride(name = "plan", column = @Column(name = "epp_plan", nullable = false)),
@AttributeOverride(name = "employerProductsNo", column = @Column(name = "employer_products_no", nullable = false)) })
private EmployerProductsPlanId id;
@ManyToOne
@JoinColumn(name = "employer_products_no")
@MapsId("employerProductsNo")
private EmployerProducts employerProducts;
}
我正在用正在保存的employerproducts对象的相同示例填充上面的employerproducts。它是暂时的,没有填充id,因为它还不存在于db中。
员工产品计划ID
@Accessors(chain = true) // has to come before @Getter and @Setter
@lombok.Getter
@lombok.Setter
@lombok.EqualsAndHashCode(of = {"plan", "employerProductsNo"})
@Embeddable
public class EmployerProductsPlanId implements Serializable {
private String plan;
private Long employerProductsNo;
// This was my previous mapping that was causing the internal NPE in hibernate
/* @ManyToOne
@JoinColumn(name = "employer_products_no")
private EmployerProducts employerProducts;*/
}
更新:显示struts控制器和dao。在保存之前,从不从db加载employer对象。struts正在从http请求参数创建整个对象图。
struts 2.5控制器
@lombok.Getter
@lombok.Setter
public class EditEmployers extends ActionHelper implements Preparable {
@Autowired
@lombok.Getter(AccessLevel.NONE)
@lombok.Setter(AccessLevel.NONE)
private IEmployerDao employerDao;
private Employer entity;
....
public String save() {
beforeSave();
boolean newRecord = getEntity().getEmployerNo() == null || getEntity().getEmployerNo() == 0;
Employer savedEmployer = newRecord ?
employerDao.create(getEntity()) :
employerDao.update(getEntity());
setEntity(savedEmployer);
return "success";
}
private void beforeSave() {
Employer emp = getEntity();
// associate this employer record with any products attached
for (EmployerProducts employerProduct : emp.getEmployerProductsList()) {
employerProduct.setEmployer(emp);
employerProduct.getEmployerProductsPlanList().forEach(x ->
x.setEmployerProducts(employerProduct));
}
// check to see if branding needs to be NULL. It will create the object from the select parameter with no id
// if a branding record has not been selected
if (emp.getBranding() != null && emp.getBranding().getBrandingNo() == null) {
emp.setBranding(null);
}
}
}
雇主dao
@Repository
@Transactional
@Service
@Log4j
public class EmployerDao extends WebexchangeBaseDao implements IEmployerDao {
private Criteria criteria() {
return getCurrentSession().createCriteria(Employer.class);
}
@Override
@Transactional(readOnly = true)
public Employer read(Serializable id) {
return (Employer)getCurrentSession().load(Employer.class, id);
}
@Override
public Employer create(Employer employer) {
getCurrentSession().persist(employer);
return employer;
}
@Override
public Employer update(Employer employer) {
getCurrentSession().merge(employer);
return employer;
}
}
1条答案
按热度按时间8ljdwjyq1#
目前为止,我的解决方案是循环浏览EmployeerProducts并检查新记录。在对父雇主调用merge()之前,我对新雇主调用了persist。我还将关联所有键的逻辑移到dao中,而不是在struts操作中。下面是我在雇主dao中的update()方法现在的样子