二进制文件ioexception

hs1ihplo  于 2021-07-09  发布在  Java
关注(0)|答案(2)|浏览(556)

所以，我已经有三个星期的家庭作业问题了，我不知道怎么解决它。
我必须写一个程序，将搜索一个二进制文件的数字类型int和程序写他们从最小到最大。文件只能包含int类型的数字。
以下是我的程序：

  1. import java.io.DataInputStream;
  2.     import java.io.FileInputStream;
  3.     import java.io.FileNotFoundException;
  4.     import java.io.EOFException;
  5.     import java.io.IOException;
  6.     import java.util.Arrays;
  8.     public class BinaryFile
  9.     {
  10.       public static void main(String[] args) throws IOException
  11.       {
  12.         int[] numArray = new int[10];
  13.         try 
  14.         {
  15.           DataInputStream inputStream = new DataInputStream(new FileInputStream("numbers.dat")); //creates an object that reads from numbers.dat
  16.           System.out.println("Reading the integers from numbers.dat");
  17.           int i;
  18.           for(i = 0;i < 10;i++) //takes the numbers from number.dat and puts them in numArray
  19.           {
  20.             numArray[i] = inputStream.readInt();
  21.           }
  22.           inputStream.close();
  23.         }
  24.         catch(EOFException e)
  25.         {
  26.           System.out.println("End of file reached");
  27.         }
  28.         catch(FileNotFoundException e)
  29.         {
  30.           System.out.println("numbes.dat not found");
  31.           System.exit(0);
  32.         }
  33.         catch(IOException e)
  34.         {
  35.           System.out.println("IOException found");
  36.           e.printStackTrace;
  37.           System.exit(0);
  38.         }
  39.         catch(Exception e)
  40.         {
  41.           System.out.println("Other exception found.");
  42.           System.exit(0);
  43.         }
  44.         System.out.println("Re-ordering numbers.");
  45.         Arrays.sort(numArray); //reorders the numbers in the array
  46.         for(int j = 0; j < 10; j++) //prints out the numbers in the array
  47.         {
  48.           System.out.println(numArray[j]);
  49.         }
  50.       }
  51.     }

输出如下：

  1. Reading the integers from numbers.dat
  2.     End of file reached
  3.     java.io.EOFException
  4.         at java.io.DataInputStream.readInt(Unknown Source)
  5.         at BinaryFile.main(BinaryFile.java:23)
  6.         at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
  7.         at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
  8.         at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
  9.         at java.lang.reflect.Method.invoke(Unknown Source)
  10.         at edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:272)
  11.         at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
  12.         at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
  13.         at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
  14.         at java.lang.reflect.Method.invoke(Unknown Source)
  15.         at edu.rice.cs.dynamicjava.symbol.JavaClass$JavaMethod.evaluate(JavaClass.java:362)
  16.         at edu.rice.cs.dynamicjava.interpreter.ExpressionEvaluator.handleMethodCall(ExpressionEvaluator.java:92)
  17.         at edu.rice.cs.dynamicjava.interpreter.ExpressionEvaluator.visit(ExpressionEvaluator.java:84)
  18.         at koala.dynamicjava.tree.StaticMethodCall.acceptVisitor(StaticMethodCall.java:121)
  19.         at edu.rice.cs.dynamicjava.interpreter.ExpressionEvaluator.value(ExpressionEvaluator.java:38)
  20.         at edu.rice.cs.dynamicjava.interpreter.ExpressionEvaluator.value(ExpressionEvaluator.java:37)
  21.         at edu.rice.cs.dynamicjava.interpreter.StatementEvaluator.visit(StatementEvaluator.java:106)
  22.         at edu.rice.cs.dynamicjava.interpreter.StatementEvaluator.visit(StatementEvaluator.java:29)
  23.         at koala.dynamicjava.tree.ExpressionStatement.acceptVisitor(ExpressionStatement.java:101)
  24.         at edu.rice.cs.dynamicjava.interpreter.StatementEvaluator.evaluateSequence(StatementEvaluator.java:66)
  25.         at edu.rice.cs.dynamicjava.interpreter.Interpreter.evaluate(Interpreter.java:77)
  26.         at edu.rice.cs.dynamicjava.interpreter.Interpreter.interpret(Interpreter.java:47)
  27.         at edu.rice.cs.drjava.model.repl.newjvm.InterpreterJVM.interpret(InterpreterJVM.java:246)
  28.         at edu.rice.cs.drjava.model.repl.newjvm.InterpreterJVM.interpret(InterpreterJVM.java:220)
  29.         at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
  30.         at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
  31.         at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
  32.         at java.lang.reflect.Method.invoke(Unknown Source)
  33.         at sun.rmi.server.UnicastServerRef.dispatch(Unknown Source)
  34.         at sun.rmi.transport.Transport$1.run(Unknown Source)
  35.         at sun.rmi.transport.Transport$1.run(Unknown Source)
  36.         at java.security.AccessController.doPrivileged(Native Method)
  37.         at sun.rmi.transport.Transport.serviceCall(Unknown Source)
  38.         at sun.rmi.transport.tcp.TCPTransport.handleMessages(Unknown Source)
  39.         at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run0(Unknown Source)
  40.         at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.lambda$run$240(Unknown Source)
  41.         at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler$$Lambda$1/15621596.run(Unknown Source)
  42.         at java.security.AccessController.doPrivileged(Native Method)
  43.         at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run(Unknown Source)
  44.         at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
  45.         at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
  46.         at java.lang.Thread.run(Unknown Source)
  47.     Re-ordering numbers.
  48.     0
  49.     0
  50.     0
  51.     0
  52.     540090425
  53.     540483633
  54.     807416628
  55.     825368627
  56.     891304224
  57.     941634610

基本上，它拒绝从numbers.dat读取数字。我不太确定问题出在哪里。
我在numbers.dat中使用的数字是：5 9 12 3 7 10 34 1 98 42

JavabinaryfilesIOException

2条答案

按热度按时间
nvbavucw

nvbavucw1#

要解析文件，请使用scanner。

  1. import java.io.File;
  2. import java.io.FileNotFoundException;
  3. import java.io.IOException;
  4. import java.util.Arrays;
  5. import java.util.Scanner;
  7. public class BinaryFile
  8. {
  9.   public static void main(String[] args) throws IOException
  10.   {
  11.     Integer[] numArray = new Integer[10];
  12.     try 
  13.     {
  14.       Scanner inputStream = new Scanner(new File("D:/abc.dat")); //creates an object that reads from numbers.dat
  15.       System.out.println("Reading the integers from numbers.dat");
  16.       int i;
  17.       for(i = 0;i < 10;i++) //takes the numbers from number.dat and puts them in numArray
  18.       {
  19.         numArray[i] = inputStream.nextInt();
  20.       }
  21.       inputStream.close();
  22.     }
  23.     catch(FileNotFoundException e)
  24.     {
  25.       System.out.println("numbes.dat not found");
  26.       System.exit(0);
  27.     }
  28.     catch(IOException e)
  29.     {
  30.       System.out.println("IOException found");
  31.       e.printStackTrace();
  32.       System.exit(0);
  33.     }
  34.     catch(Exception e)
  35.     {
  36.       System.out.println("Other exception found.");
  37.       System.exit(0);
  38.     }
  39.     System.out.println("Re-ordering numbers.");
  40.     Arrays.sort(numArray); //reorders the numbers in the array
  41.     for(int j = 0; j < 10; j++) //prints out the numbers in the array
  42.     {
  43.       System.out.println(numArray[j]);
  44.     }
  45.   }
  46. }
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u5i3ibmn

u5i3ibmn2#

所以对象输入流并不是您真正想要的。
使用datainputstream会更好。

  1. DataInputStream inputStream = new DataInputStream(new FileInputStream("numbers.dat"));
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