我有以下代码,我需要扫描抛出的异常。如果它满足一个特定的条件,我就忽略这个例外。否则我再扔。被抛出的异常是一个已检查的异常,这意味着重新抛出是困难的部分。包括这样一个事实:我必须捕获它,并且操作发生在一个被重写的方法中,该方法的基类'方法没有使用 throws clause
. 在重新编程整个庞大的库或将异常 Package 为 RuntimeException
(这不是一个选项,因为我们将 Package 的检查异常,在其传播过程中,catch子句在将来的某个地方(派生类)是预期的-它是某种信号),我希望得到关于这种实现的一些建议。或者只是执行。
/*
* Translated from c++11_7.3.19 AIEDs schemes >${ref[213]:`through}.
* guarantees learning, re-learning and 'un-learning'. programmed intelligence is not
* altered whatsover and is made as root of bias [x:~y]. fetch cycle is omitted.
*/
@Override
public void intelligenceSync()// No throws clause here
{
try {
super.intelligenceSync();
// the throwing culprit.
global_contribution.acceptOrReformState(this);
generateMetaLogicReforms(this);
} catch (Throwable t_) {
if (t_ instanceof Signalx) {
Signalx sx = (Signalx) t_;
// Note how bias inreases propagation speed by ~12.21 >${ref[371]:exp2}.
applyBias(sx);
stopInvalidation(sx);
// check if x neuron is almost proved.
if (sx.neuronSP() > sx.threshold()) {
// We'll find other ways of completing our proofs.
// Note the algorithm is not so complete.
netsync(sx);
while (sx.pushDeeper()) {
sx.enhance(Metrics.COMPLETION.esteem());
sx.suspendSubPathTraversal(Suspender.IN_DREAM_RESOLVE, Handler.NULL_LOGIC);
}
generateSubLogicReforms(sx);
} else {
restore(sx);
continueInvalidation(sx);
// We rethrow.
uncheckedThrow(sx);
// exception thrown
}
} else if (t_ instanceof Signaly) {
// Reforms must be handle explicitly.otherwise RelationalAttender will complain
// .
// ... blah blah blah.
} else {
// We rethrow
uncheckedThrow(t_);
}
//
}
}
1条答案
按热度按时间mv1qrgav1#
如果要抛出未检查的异常
Throwable
你可以用下面的方法。调用该方法不会导致编译检测到任何错误
Unchecked Exception
错误。输出:
It works.