hibernate/api

vhmi4jdf  于 2021-07-12  发布在  Java
关注(0)|答案(1)|浏览(260)

我遇到了以下问题:我想简单地加入表markets(main)和telephones,但是在使用注解执行此操作时遇到了一些问题。
我只想使用comercio.id作为telefone.fkïid的对应外键,但它无法识别它。我还想问一下是否需要为这两个类创建一个存储库接口。
编辑。另外,对于这样一个例子,post-req看起来怎么样?
科梅西奥.java

@Entity
@Table(name = "comercio")
public class Comercio {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String nome;
    private String cnpj;
    private String endereco;

    @OneToMany(targetEntity = Telefone.class , mappedBy = "comercio", fetch = FetchType.LAZY)
    private List<Telefone> telefones;
    private String email;

电话.java

@Entity
@Table(name = "telefone")
public class Telefone {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long telefone_id;

    @ManyToOne
    @JoinColumn(name="fk_id", referencedColumnName = "id")
    private Comercio comercio;
    private String telefone;

我得到的答案是:

{
      "nome" : "Americanas",
      "cnpj" : "000",
      "endereco" : "SQN 112",
      "telefones" : [ ],
      "email" : "contato@americanas.com",
      "comercio_id" : 1
}

慰问:

Hibernate: select comercio0_.id as id1_0_, comercio0_.cnpj as cnpj2_0_, comercio0_.email as email3_0_, comercio0_.endereco as endereco4_0_, comercio0_.nome as nome5_0_ from comercio comercio0_
Hibernate: select telefones0_.fk_id as fk_id3_1_0_, telefones0_.telefone_id as telefone1_1_0_, telefones0_.telefone_id as telefone1_1_1_, telefones0_.fk_id as fk_id3_1_1_, telefones0_.telefone as telefone2_1_1_ from telefone telefones0_ where telefones0_.fk_id=**?**

感谢你的帮助。

ztyzrc3y

ztyzrc3y1#

我认为电话本身并不是一个实体:你永远不会想要查询电话,它只作为comercio的一部分存在。
然后可能是 Embeddable 但是,与实体不同的是,它只有一个属性-数字-然后您可以简化为下面的内容,并将其Map为字符串的集合。那么就不需要一个 Telefone 班级。

@Entity
@Table(name = "comercio")
public class Comercio {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String nome;
    private String cnpj;
    private String endereco;

    @ELementCollection
    @CollectionTable(name = "comercio_telefone", 
                joinColumns=@JoinColumn(name="comercio_id"))
    private List<String> telefones;

    private String email;
}

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