我有实体

@Entity
@Table(
        name = SomeEntity.TABLE_NAME,
        uniqueConstraints = {@UniqueConstraint(columnNames = {"first", "second"})}
)
public class SomeEntity extends SomeSuperEntity {
    public static final String TABLE_NAME = "SomeEntity";

    public SomeEntity() {
    }

    public SomeEntity(String first, String second, Integer third) {
        super(first, second, third);
    }
}

此实体的超类

@MappedSuperclass
public abstract class SomeSuperEntity extends SomeSuperAbstractEntity {
    @Column(nullable = false)
    private String first;
    @Column(nullable = false)
    private String second;

    protected SomeSuperEntity () {
    }

    protected SomeSuperEntity (String first, String second, Integer third) {
        super(third);
        this.first= first;
        this.second= second;
    }
}

二等舱

@MappedSuperclass
public abstract class SomeSuperAbstractEntity {
    @Column(nullable = false)
    private Integer third;

    protected SomeSuperAbstractEntity () {
    }

    protected SomeSuperAbstractEntity (Integer third) {
        this.third= third;
    }
}

我有两个方法，第一个是查找实体

public <T extends SomeSuperEntity > Optional<T> findByFirstAndSecond(String first, String second, Class<T> tClass) {
        String hql = String.format("FROM %s E WHERE E.first = :first AND E.second = :second", getTable(tClass));
        return jpaApi.em().createQuery(hql, tClass)
                .setParameter("first", first)
                .setParameter("second", second)
                .getResultList().stream().findAny();
    }

第二个用于将实体名称获取到hql

private String getTable(Class<? extends SomeSuperEntity > tClass) {
    if (tClass.equals(SomeEntity .class)) {
        return SomeEntity.TABLE_NAME;
    }
    return null;
}

当我尝试调用findbyfirstandsecond（“1”，“2”，someentity.class）时，出现了错误
[错误]c.i.somemethod-错误：org.hibernate.hql.internal.ast.querysyntaxexception:someentity未Map[来自someentity e，其中e.first=：first和e.second=：second]