我想从json数组中删除多个json,我有一个如下所示的json源代码格式。我有一个列表,其中包含需要保存在json数组中的设备id列表,其余的需要删除。例如,如我的源代码json所示,我有3个 dev_id 100010100 , 200020200 and 300030300
.
我有Python名单 device_id_list=[200020200,300030300]
,我的最终json数组应该只包含2个json,dev_id=100010100的json将被删除,如输出json所示。
我尝试了一个可能不是最佳的选择,我的方法是将json作为字符串而不是json读取,如下所示。
df = spark.read.text("path\\iot-sensor.json")
df:pyspark.sql.dataframe.DataFrame
value:string
我已经编写了一个udf来删除json文件中不存在的json文件 device_id_list
. 它正在删除 dev_id
不存在,并以字符串形式返回json。
我要这根绳子。 dataframe df2
要转换为json,使用相同的源json模式 (df2:pyspark.sql.dataframe.DataFrame = [iot_station: array] (Sorce Schema) )
因为源和输出json的模式应该是相同的,如果有更好的解决方案,请与我们分享。
自定义项:
def drop_dev_id(jsonResponse,dict_keys):
try:
data = json.loads(jsonResponse)
i = 0
n = len(data['iot_station'])
while (i < n):
if data['iot_station'][i]["dev_id"] not in dict_keys:
data['iot_station'].pop(i)
n -= 1
else:
i += 1
return data
except Exception as e:
print('Exception --> ' + str(e))
def drop_dev_id_udf(dict_keys):
return udf(lambda row: drop_dev_id(row,dict_keys), StringType())
df2 = df.select('value',drop_dev_id_udf(dict_keys)('value')).select('<lambda>(value)')
df2:pyspark.sql.dataframe.DataFrame
<lambda>(value):string
源json
{
"iot_station": [
{
"dev_id": 100010100,
"device1": dev_val1,
"device2": "dev_val2",
"device3": dev_val3,
"device4": "dev_val4",
"stationid": [
{
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
],
"geospat": {
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
},
{
"dev_id": 200020200,
"device1": dev_val1,
"device2": "dev_val2",
"device3": dev_val3,
"device4": "dev_val4",
"stationid": [
{
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
],
"geospat": {
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
},
{
"dev_id": 300030300,
"device1": dev_val1,
"device2": "dev_val2",
"device3": dev_val3,
"device4": "dev_val4",
"stationid": [
{
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
],
"geospat": {
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
}
]
}
输出json:
{
"iot_station": [
{
"dev_id": 200020200,
"device1": dev_val1,
"device2": "dev_val2",
"device3": dev_val3,
"device4": "dev_val4",
"stationid": [
{
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
],
"geospat": {
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
},
{
"dev_id": 300030300,
"device1": dev_val1,
"device2": "dev_val2",
"device3": dev_val3,
"device4": "dev_val4",
"stationid": [
{
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
],
"geospat": {
"id": id_val,
"idrs": idrs_val,
"idrq": "idrq_val",
"idrx": "idrx_val"
}
}
]
}
1条答案
按热度按时间swvgeqrz1#
你不需要自定义项来实现你的目标。只需将其作为普通的json而不是文本加载并使用
filter
函数来筛选数组列iot_station
: