你只需要遍历你的列表，并将可能性附加到你的列表中 dinner_options 数组。

appetizer = ['soup', 'salad']
entree = ['steak', 'chicken', 'fish']
dessert = ['ice cream', 'flan', 'cake']
dinner_options = []
for ap in appetizer:
    for en in entree:
        for de in dessert:
            dinner_options.append({ "appetizer": ap, "entree": en, "dessert": de })
print(dinner_options)

然后它就会显示出来

[{'appetizer': 'soup', 'entree': 'steak', 'dessert': 'ice cream'}, {'appetizer': 'soup', 'entree': 'steak', 'dessert': 'flan'}, {'appetizer': 'soup', 'entree': 'steak', 'dessert': 'cake'}, {'appetizer': 'soup', 'entree': 'chicken', 'dessert': 'ice cream'}, {'appetizer': 'soup', 'entree': 'chicken', 'dessert': 'flan'}, {'appetizer': 'soup', 'entree': 'chicken', 'dessert': 'cake'}, {'appetizer': 'soup', 'entree': 'fish', 'dessert': 'ice cream'}, {'appetizer': 'soup', 'entree': 'fish', 'dessert': 'flan'}, {'appetizer': 'soup', 'entree': 'fish', 'dessert': 'cake'}, {'appetizer': 'salad', 'entree': 'steak', 'dessert': 'ice cream'}, {'appetizer': 'salad', 'entree': 'steak', 'dessert': 'flan'}, {'appetizer': 'salad', 'entree': 'steak', 'dessert': 'cake'}, {'appetizer': 'salad', 'entree': 'chicken', 'dessert': 'ice cream'}, {'appetizer': 'salad', 'entree': 'chicken', 'dessert': 'flan'}, {'appetizer': 'salad', 'entree': 'chicken', 'dessert': 'cake'}, {'appetizer': 'salad', 'entree': 'fish', 'dessert': 'ice cream'}, {'appetizer': 'salad', 'entree': 'fish', 'dessert': 'flan'}, {'appetizer': 'salad', 'entree': 'fish', 'dessert': 'cake'}]

您可以使用itertools.product：

from itertools import product
appetizer = ['soup', 'salad']
entree = ['steak', 'chicken', 'fish']
dessert = ['ice cream', 'flan', 'cake']
# Here we create an iterable from the objects we want to obtain
# different combinations.
to_combine = (appetizer, entree, dessert)
# Next, we need to define the order in which those appear
# as those will be used as the keys in the individual
# dictionary objects.
order = 'appetizer,entree,dessert'.split(',')
dinner_options = list()
# Now we loop over the unpacked tuple and build each individual
# dictionary.
for items in product(*to_combine):
    # This creates the individual objects which are of the form:
    # `{'appetizer': '<a>', 'entree': '<e>', 'dessert': '<d>'}
    d = {key:value for key, value in zip(order, items)}
    dinner_options.append(d)

这将产生所需的输出。

我认为这是最明显和最耗时的答案

appetizer = ['soup', 'salad']
entree = ['steak', 'chicken', 'fish']
dessert = ['ice cream', 'flan', 'cake']
# dict = {appetizer = [], entree = [], dessert = []}
dinner_options = []
for start in appetizer:
    for mid in entree:
        for end in dessert:
            data = dict(appetizer=start, entree=mid, dessert=end)
            dinner_options.append(data)
print(dinner_options)