如何在登录表单中获取输入用户名的值?
我的登录表单是:
<form th:action="@{/login}" method="post">
<div class="form-group">
<input type="text" name="username" id="username"
class="form-control" th:placeholder="Email" autofocus required/>
</div>
<div class="form-group">
<input type="password" name="password" id="password"
class="form-control" th:placeholder="Password" required/>
</div>
<input type="submit" class="btn btn-lg btn-primary btn-block"
th:value="Login"/>
</form>
我的控制器是:
@Controller
public class LoginController {
@GetMapping("/login")
public String login(@RequestParam(value = "error", required = false) String error, Model model,
Principal principal) {
if (principal != null) {
return "redirect:/ccursos";
}
if (error != null) {
model.addAttribute("msg",
"Error al iniciar sesión: Nombre de usuario o contraseña incorrecta, por favor vuelva
a intentarlo!");
}
return "login";
}
@GetMapping("/logout")
public String logoutPage (HttpServletRequest request, HttpServletResponse response) {
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
if (auth != null){
new SecurityContextLogoutHandler().logout(request, response, auth);
}
return "redirect:/login";
}
}
我试图使用@requestparam获取变量的值,但它说varible电子邮件不存在。我知道这一点,所以任何帮助将不胜感激。
我想说的是:
@GetMapping("/login")
public String login(@RequestParam(value = "error", required = false) String error,@RequestParam("Email") String email,
Model model, Principal principal) {
if (principal != null) {
return "redirect:/ppeliculas";
}
if (error != null) {
model.addAttribute("msg",
"Error al iniciar sesión: Nombre de usuario o contraseña incorrecta, por favor vuelva
a intentarlo!");
}
return "login";
}
1条答案
按热度按时间hfsqlsce1#
你想把表格寄过去
POST
方法,但您的控制器仅为@GetMapping
. 更改或添加@PostMapping
,然后添加@RequestBody Model model
(如果等级Model
描述你的形式)和所有应该工作。如果您刚开始编程,请阅读有关http的内容:https://www.w3schools.com/tags/ref_httpmethods.asp 在这种情况下
@RequestBody
: https://www.baeldung.com/spring-request-response-body