一个简单的正则表达式和 replaceAllIn() 我应该这么做。

val inLst =
  List("This is an exercise, which I have problem with"
     , "and I don't know, how to do it."
     , "text-,.")

inLst.map("[-,.\"]".r.replaceAllIn(_, ""))
//res0: List[String] = 
// List(This is an exercise which I have problem with
//    , and I don't know how to do it
//    , text)

你可以申请 regex 一次全部替换。像这样：

import scala.util.matching.Regex

val regex = "\\.*,*-*\"*".r

val sampleText = "Hi there. This comma, should be gone. and dots and quotes \"as well."
val result = regex.replaceAllIn(sampleText, "")

println(s"result: $result")
// result: Hi there This comma should be gone and dots and quotes as well

应用于示例代码时，它可能如下所示：

import scala.util.matching.Regex

val regex = "\\.*,*-*\"*".r

val result = io.Source
  .fromResource("ogniem-i-mieczem.txt")
  .getLines
  .toList
  .map { line => regex.replaceAllIn(line, "") }

println(s"Result: $result")

基于regex的其他答案是可行的，但正如学习练习所指出的，我们可以将字符串概念化为字符序列，这意味着我们可以将它们视为集合，这样通常的可疑Map/过滤器等也可以工作

lines map { _.filterNot { exclusionList.contains } }

哪里

val exclusionList = Set(',', '.', '-', '"')