有人能解释一下arrayjoin()函数在clickhouse数据库中是如何工作的吗?

qxsslcnc  于 2021-07-15  发布在  ClickHouse
关注(0)|答案(1)|浏览(316)

我是clickhouse数据库的新手,文档中提供的示例无助于正确理解这个概念。请解释如何将arrayjoin()用于简单场景。

yqkkidmi

yqkkidmi1#

让我们考虑下一个场景:
需要将数组转换为关系(行集)时

/* get error */
SELECT 1
WHERE 1 IN ([1, 2]);

/* ok */
SELECT 1
WHERE 1 IN (SELECT arrayJoin([1, 2]));
/* get error */
SELECT *
FROM (SELECT [1, 2] a)
WHERE a = 2;

/* ok */
SELECT *
FROM (SELECT arrayJoin([1, 2]) a)
WHERE a = 2;

展开/展平行

SELECT
    metric_id,
    metric_name,
    arrayJoin(metric_values) AS metric_value
FROM
( /* test data */
    SELECT
        1 AS metric_id,
        'name_1' AS metric_name,
        [1, 4, 55] AS metric_values
    UNION ALL
    SELECT
        2 AS metric_id,
        'name_2' AS metric_name,
        [-7, 11] AS metric_values
)
/* result
┌─metric_id─┬─metric_name─┬─metric_value─┐
│         1 │ name_1      │            1 │
│         1 │ name_1      │            4 │
│         1 │ name_1      │           55 │
│         2 │ name_2      │           -7 │
│         2 │ name_2      │           11 │
└───────────┴─────────────┴──────────────┘

* /
/* produce Cartesian product */
SELECT
    arrayJoin([1, 2]) AS n,
    arrayJoin(['a', 'b']) AS ll,
    arrayJoin(['A', 'B']) AS ul
/* result
┌─n─┬─ll─┬─ul─┐
│ 1 │ a  │ A  │
│ 1 │ a  │ B  │
│ 1 │ b  │ A  │
│ 1 │ b  │ B  │
│ 2 │ a  │ A  │
│ 2 │ a  │ B  │
│ 2 │ b  │ A  │
│ 2 │ b  │ B  │
└───┴────┴────┘

* /
/* flatten the multidimension array */
SELECT arrayJoin(arrayJoin([[1, 2], [3, 4]])) AS d
/* result
┌─d─┐
│ 1 │
│ 2 │
│ 3 │
│ 4 │
└───┘

* /

当需要逐项链接数组而不是获得笛卡尔积时,请考虑使用数组联接:

/* cartesian product */

SELECT
    arrayJoin(arr1),
    arrayJoin(arr2)
FROM
(
    SELECT
        [1, 2] AS arr1,
        [11, 22] AS arr2
)

/*
┌─arrayJoin(arr1)─┬─arrayJoin(arr2)─┐
│               1 │              11 │
│               1 │              22 │
│               2 │              11 │
│               2 │              22 │
└─────────────────┴─────────────────┘

* /

/* connect array's item one by one */

SELECT a1, a2, arr1, arr2
FROM
(
    SELECT
        [1, 2] AS arr1,
        [11, 22] AS arr2
)
ARRAY JOIN arr1 as a1, arr2 as a2

/*
┌─a1─┬─a2─┬─arr1──┬─arr2────┐
│  1 │ 11 │ [1,2] │ [11,22] │
│  2 │ 22 │ [1,2] │ [11,22] │
└────┴────┴───────┴─────────┘

* /

相关问题