我经常将json作为请求体的一部分传递给spring控制器。不是为了我的生活,我不能让这个工作?给我400个坏请求。
Spring控制器:
@RequestMapping(value = "/saverefunds", method = RequestMethod.POST)
@ResponseBody
public String saveRefunds(Model model, HttpSession session, AS400WriteRefundLine as400WriteRefundLine, @RequestBody CreateRefund refunddetails) throws ParseException, IOException {
////
}
调用它的javascript代码:
let refunddetails = {
blackbookno: refundedInvoiceNo,
RfExno: "00",
transactionType: "R",
stockid: stockid,
sku: sku,
refundtype: refundtype,
refundreason: refundreason,
btsflag: btsflag,
uniqueid: uniqueid,
thisrefundamount: thisrefund,
firstrecord: firstRecord.toString(),
nextRfEx:"1",
firstname: wFname,
surname: wLname,
address1: wAdd1,
address2: wAdd2,
town: wTown,
county: wCounty,
landline: wTelno,
mobile: wMobile,
email: wEmail
};
await $.ajax({
type: 'POST',
contentType: 'application/json; charset=utf-8',
url: "saverefunds",
data: JSON.stringify(refunddetails),
success: function (data) {
alert(data);
if (data.substring(0, 2) != "OK:") {
// ERROR
alert("postErr: " + data);
} else {
alert('Refund Generated');
}
return true;
},
error: function (error) {
alert('ERROR:'+error.responseText);
}
});
createrefund对象:
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@JsonIgnoreProperties
public class CreateRefund {
private String blackbookno, RfExno, transactionType, stockid, sku, refundtype, refundreason, btsflag,
uniqueid, thisrefundamount, firstrecord, nextRfEx, firstname,
surname, address1, address2, town, county, landline, mobile, email;
}
pojo与正在传递的json匹配,所以不确定它还能是什么?
有人看到什么明显的错误吗?
我可以传递数据的唯一方法是在spring控制器中使用map<string,string>,而不是createreturn对象…所以我假设jsonMap不起作用?
非常感谢
1条答案
按热度按时间k0pti3hp1#
错误是在发送之前将数据转换为字符串。
也
到底是什么
AS400WriteRefundLine as400WriteRefundLine
Spring又如何知道该把什么价值放在那里呢?