如何在控制器中获取用户电子邮件地址？
我正在尝试获取控制器中试图登录的用户的电子邮件地址，但由于某些原因被阻止。我想通知用户，此电子邮件地址的用户已被阻止。但是为了这个，我需要得到他的电子邮件地址。
问题！如何在控制器中获取用户电子邮件地址？
我有securityconfig，userdetail，logincontroller。
在这里我添加了整个项目-https://github.com/romanych2021/mytest 专门为这个问题做的
证券配置

package com.mytest.security;

    import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
    import org.springframework.security.config.annotation.web.builders.HttpSecurity;
    import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
    import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
    import org.springframework.security.core.userdetails.UserDetailsService;

    @EnableWebSecurity
    public class SecurityConfig extends WebSecurityConfigurerAdapter {

        private final
        UserDetailsService userDetailsService;

        public SecurityConfig(UserDetailsService userDetailsService) {
            this.userDetailsService = userDetailsService;
        }

        @Override
        protected void configure(AuthenticationManagerBuilder auth) throws Exception {
            auth.userDetailsService(userDetailsService);
        }

        @Override
        protected void configure(HttpSecurity http) throws Exception {
            http
                    .authorizeRequests()

                    .mvcMatchers("/login").anonymous()
                    .mvcMatchers("/user/**").hasRole("USER")

                    .and()
                    .csrf().disable()
                    .formLogin()
                    .loginPage("/login")
                    .loginProcessingUrl("/login")
                    .defaultSuccessUrl("/")
                    .failureUrl("/login?error=true")
                    .usernameParameter("email")
                    .passwordParameter("password")

                    .and()
                    .exceptionHandling()
                    .accessDeniedPage("/403")

                    .and()
                    .logout()
                    .permitAll()
                    .logoutUrl("/logout")
                    .logoutSuccessUrl("/")

                    .invalidateHttpSession(true)
                    .deleteCookies("JSESSIONID");
        }

    }

用户详细信息

package com.mytest.security;

    import com.mytest.model.User;
    import com.mytest.service.UserRepository;

    import org.springframework.beans.factory.annotation.Autowired;
    import org.springframework.security.core.GrantedAuthority;
    import org.springframework.security.core.authority.SimpleGrantedAuthority;
    import org.springframework.security.core.userdetails.UserDetails;
    import org.springframework.security.core.userdetails.UserDetailsService;
    import org.springframework.security.core.userdetails.UsernameNotFoundException;
    import org.springframework.stereotype.Service;

    import java.util.ArrayList;
    import java.util.Collection;
    import java.util.List;

    @Service
    public class UserDetail implements UserDetailsService {

        @Autowired
        UserRepository userRepository;

        @Override
        public UserDetails loadUserByUsername(String email) throws UsernameNotFoundException {

            User user = userRepository.findUserByEmail(email);

            if (user == null){
                throw new UsernameNotFoundException("There is no such user " + email);
            }

            return new org.springframework.security.core.userdetails.User(
                    user.getEmail(),
                    user.getPassword(),
                    user.getEnabled(),
                    user.getAccount_non_expired(),
                    user.getCredentials_non_expired(),
                    user.getAccount_non_locked(),
                    getAuthorities());

        }

        private Collection<? extends GrantedAuthority> getAuthorities(){

            List<SimpleGrantedAuthority> authList = new ArrayList<>();
            authList.add(new SimpleGrantedAuthority("ROLE_USER"));

            return authList;

        }

    }

登录控制器

package com.mytest.controller;

    import org.springframework.stereotype.Controller;
    import org.springframework.web.bind.annotation.GetMapping;

    @Controller
    public class LoginController {

        @GetMapping(value = "/login")
        public String loginGet () {

            // How do I get the user's email address here?

            return "login";
        }

    }