我使用jpa工具创建了实体类,它为没有主键的表创建了两个类。一个是@entity class,另一个是@embeddeble class,下面是这两个类的代码
国家语言
package com.geolocation.entities;
import java.io.Serializable;
import javax.persistence.*;
/**
* The persistent class for the countrylanguage database table.
*
*/
@Entity
@NamedQuery(name="Countrylanguage.findAll", query="SELECT c FROM Countrylanguage c")
public class Countrylanguage implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
private CountrylanguagePK id;
private String isOfficial;
private String language;
private float percentage;
//bi-directional many-to-one association to Country
@ManyToOne
@JoinColumn(name="CountryCode")
private Country country;
public Countrylanguage() {
}
// public CountrylanguagePK getId() {
// return this.id;
// }
//
// public void setId(CountrylanguagePK id) {
// this.id = id;
// }
public String getIsOfficial() {
return this.isOfficial;
}
public void setIsOfficial(String isOfficial) {
this.isOfficial = isOfficial;
}
public String getLanguage() {
return this.language;
}
public void setLanguage(String language) {
this.language = language;
}
public float getPercentage() {
return this.percentage;
}
public void setPercentage(float percentage) {
this.percentage = percentage;
}
public Country getCountry() {
return this.country;
}
public void setCountry(Country country) {
this.country = country;
}
}
国家语言PK
package com.geolocation.entities;
import java.io.Serializable;
import javax.persistence.*;
/**
* The primary key class for the countrylanguage database table.
*
*/
@Embeddable
public class CountrylanguagePK implements Serializable {
//default serial version id, required for serializable classes.
private static final long serialVersionUID = 1L;
@Column(insertable=false, updatable=false)
private String countryCode;
private String language;
public CountrylanguagePK() {
}
public String getCountryCode() {
return this.countryCode;
}
public void setCountryCode(String countryCode) {
this.countryCode = countryCode;
}
public String getLanguage() {
return this.language;
}
public void setLanguage(String language) {
this.language = language;
}
public boolean equals(Object other) {
if (this == other) {
return true;
}
if (!(other instanceof CountrylanguagePK)) {
return false;
}
CountrylanguagePK castOther = (CountrylanguagePK)other;
return
this.countryCode.equals(castOther.countryCode)
&& this.language.equals(castOther.language);
}
public int hashCode() {
final int prime = 31;
int hash = 17;
hash = hash * prime + this.countryCode.hashCode();
hash = hash * prime + this.language.hashCode();
return hash;
}
}
执行时抛出错误。。
org.springframework.beans.factory.beancreationexception:创建名为“entitymanagerfactory”的bean时出错,该bean在类路径资源[org/springframework/boot/autoconfigure/orm/jpa/hibernatejpaconfiguration.class]中定义:调用init方法失败;嵌套异常为javax.persistence.persistenceexception:[persistenceunit:default]无法构建hibernate sessionfactory;嵌套异常为org.hibernate.mappingexception:repeated column in mapping for entity:com.geolocation.entities.countrylanguage column:country\u code(应使用insert=“false”update=“false”Map)
原因:javax.persistence.persistenceexception:[persistenceunit:default]无法构建hibernate sessionfactory;嵌套异常为org.hibernate.mappingexception:repeated column in mapping for entity:com.geolocation.entities.countrylanguage column:country\u code(应使用insert=“false”update=“false”Map)
原因:org.hibernate.mappingexception:实体Map中的重复列:com.geolocation.entities.countrylanguage列:国家代码(应使用insert=“false”update=“false”Map)
1条答案
按热度按时间ibrsph3r1#
嵌入类型不应使用
insertable = false, updatable = false
但是@JoinColumn
的@ManyToOne
联想。