spring引导:save to repository不适用于@transactional(propagation=propagation.requires\ new)

34gzjxbg  于 2021-07-24  发布在  Java
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我的应用程序分为几个模块,我想创建一个新的“确认注册令牌”模块,它独立于“用户”模块的Angular 。您可以猜到,该模块负责通过电子邮件验证令牌启用用户帐户。因此,我创建了一个与用户有一对一关系的实体:

@Entity
public class ConfirmRegistrationToken {
    @Id
    private Long id;

    @MapsId
    @OneToOne(optional = false, fetch = FetchType.LAZY)
    private User user;

    private String token;

    private LocalDateTime expiresAt;

    // setters, getters, etc.

我正在侦听在userservice中发布的onuserregisterevent:

@Transactional
    public UserModel register(UserRegisterModel model) {
        validatorsExecutor.validate(
            new UserRegisterValidator(model, userRepository)
        );

        User user = userRegisterMapper.toObject(model);
        user = userRepository.save(user);
        eventPublisher.publishEvent(new OnUserRegisterEvent(user));
        return userMapper.toModel(user);
    }

然后,在用@transactionaleventlistener注解的侦听器中激发createtoken:

@Component
public class OnUserRegisterListener {
    private final ConfirmRegistrationTokenGenerator tokenGenerator;

    @Autowired
    public OnUserRegisterListener(ConfirmRegistrationTokenGenerator tokenGenerator) {
        this.tokenGenerator = tokenGenerator;
    }

    @TransactionalEventListener
    public void onApplicationEvent(OnUserRegisterEvent event) {
        tokenGenerator.createToken(event.getUser());
    }
}

createtoken方法被注解为@transactional(propagation=propagation.requires\u new),因为我想在新的独立事务中激发此方法:

@Transactional(propagation = Propagation.REQUIRES_NEW)
    public void createToken(User user) {
        ConfirmRegistrationToken token = new ConfirmRegistrationToken();
        token.setUser(user);

        String generatedToken = UUID.randomUUID().toString();
        token.setToken(generatedToken);

        Integer expirationHours = environment.getProperty("user.confirm-registration.expiration-hours", Integer.class, 24);
        token.setExpiresAt(LocalDateTime.now().plus(Duration.ofHours(expirationHours)));
        confirmRegistrationTokenRepository.save(token);

        //TODO implement sending message here
        System.out.println("To confirm your registration, just click here: http://localhost:8080/user/" + user.getId() + "/confirmRegistration/" + generatedToken);
    }

但不幸的是,将令牌保存到数据库不起作用,查询甚至没有发送到数据库:

Hibernate: select user0_.id as id1_3_, user0_.email as email2_3_, user0_.enabled as enabled3_3_, user0_.encoded_password as encoded_4_3_, user0_.name as name5_3_ from users user0_ where user0_.email=?
Hibernate: select user0_.id as id1_3_, user0_.email as email2_3_, user0_.enabled as enabled3_3_, user0_.encoded_password as encoded_4_3_, user0_.name as name5_3_ from users user0_ where user0_.name=?
Hibernate: insert into users (email, enabled, encoded_password, name) values (?, ?, ?, ?)

我已经测试过用@transactional和默认值在其他方法中保存这个令牌,它是有效的,但这里没有,我很困惑,因为这里没有任何异常。我做错什么了吗?

kkih6yb8

kkih6yb81#

如果你用的是简单的 @Transactional 进入第二种方法,事务仍然是相同的,所以它可以工作。
我认为这是因为您传递的实体已经保存在上一个事务中。 User -> createToken @事务方法在事务结束时自动反映在数据库中,但它仅适用于在此特定事务中保存、合并或检索的实体。
通常,在不同的事务上下文之间传递实体不是一个好主意。如果在新事务中需要,应该传递唯一的id并再次获取整个实体。
以下是一篇关于你的问题的好文章:https://codete.com/blog/spring-transaction-propagation-modes/
我相信这会对你有帮助。
代码示例:

@Transactional(propagation = Propagation.REQUIRES_NEW)
public void createToken(long userId) {
    User user = userRepository.findById(userId).get();
    ConfirmRegistrationToken token = new ConfirmRegistrationToken();
    token.setUser(user);

    String generatedToken = UUID.randomUUID().toString();
    token.setToken(generatedToken);

    Integer expirationHours = environment.getProperty("user.confirm-registration.expiration-hours", Integer.class, 24);
    token.setExpiresAt(LocalDateTime.now().plus(Duration.ofHours(expirationHours)));
    confirmRegistrationTokenRepository.save(token);

    //TODO implement sending message here
    System.out.println("To confirm your registration, just click here: http://localhost:8080/user/" + user.getId() + "/confirmRegistration/" + generatedToken);
}

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