我的应用程序分为几个模块,我想创建一个新的“确认注册令牌”模块,它独立于“用户”模块的Angular 。您可以猜到,该模块负责通过电子邮件验证令牌启用用户帐户。因此,我创建了一个与用户有一对一关系的实体:
@Entity
public class ConfirmRegistrationToken {
@Id
private Long id;
@MapsId
@OneToOne(optional = false, fetch = FetchType.LAZY)
private User user;
private String token;
private LocalDateTime expiresAt;
// setters, getters, etc.
我正在侦听在userservice中发布的onuserregisterevent:
@Transactional
public UserModel register(UserRegisterModel model) {
validatorsExecutor.validate(
new UserRegisterValidator(model, userRepository)
);
User user = userRegisterMapper.toObject(model);
user = userRepository.save(user);
eventPublisher.publishEvent(new OnUserRegisterEvent(user));
return userMapper.toModel(user);
}
然后,在用@transactionaleventlistener注解的侦听器中激发createtoken:
@Component
public class OnUserRegisterListener {
private final ConfirmRegistrationTokenGenerator tokenGenerator;
@Autowired
public OnUserRegisterListener(ConfirmRegistrationTokenGenerator tokenGenerator) {
this.tokenGenerator = tokenGenerator;
}
@TransactionalEventListener
public void onApplicationEvent(OnUserRegisterEvent event) {
tokenGenerator.createToken(event.getUser());
}
}
createtoken方法被注解为@transactional(propagation=propagation.requires\u new),因为我想在新的独立事务中激发此方法:
@Transactional(propagation = Propagation.REQUIRES_NEW)
public void createToken(User user) {
ConfirmRegistrationToken token = new ConfirmRegistrationToken();
token.setUser(user);
String generatedToken = UUID.randomUUID().toString();
token.setToken(generatedToken);
Integer expirationHours = environment.getProperty("user.confirm-registration.expiration-hours", Integer.class, 24);
token.setExpiresAt(LocalDateTime.now().plus(Duration.ofHours(expirationHours)));
confirmRegistrationTokenRepository.save(token);
//TODO implement sending message here
System.out.println("To confirm your registration, just click here: http://localhost:8080/user/" + user.getId() + "/confirmRegistration/" + generatedToken);
}
但不幸的是,将令牌保存到数据库不起作用,查询甚至没有发送到数据库:
Hibernate: select user0_.id as id1_3_, user0_.email as email2_3_, user0_.enabled as enabled3_3_, user0_.encoded_password as encoded_4_3_, user0_.name as name5_3_ from users user0_ where user0_.email=?
Hibernate: select user0_.id as id1_3_, user0_.email as email2_3_, user0_.enabled as enabled3_3_, user0_.encoded_password as encoded_4_3_, user0_.name as name5_3_ from users user0_ where user0_.name=?
Hibernate: insert into users (email, enabled, encoded_password, name) values (?, ?, ?, ?)
我已经测试过用@transactional和默认值在其他方法中保存这个令牌,它是有效的,但这里没有,我很困惑,因为这里没有任何异常。我做错什么了吗?
1条答案
按热度按时间kkih6yb81#
如果你用的是简单的
@Transactional
进入第二种方法,事务仍然是相同的,所以它可以工作。我认为这是因为您传递的实体已经保存在上一个事务中。
User
->createToken
@事务方法在事务结束时自动反映在数据库中,但它仅适用于在此特定事务中保存、合并或检索的实体。通常,在不同的事务上下文之间传递实体不是一个好主意。如果在新事务中需要,应该传递唯一的id并再次获取整个实体。
以下是一篇关于你的问题的好文章:https://codete.com/blog/spring-transaction-propagation-modes/
我相信这会对你有帮助。
代码示例: