在sql server中创建日历表

ckx4rj1h  于 2021-07-24  发布在  Java
关注(0)|答案(1)|浏览(474)

我正在使用microsoft sql server 2012并创建下表:

Clinic_code Clinic_name        D        D_days_passed
------------------------------------------------------
   A123       NAME1       2018-12-01         1      
   A124       NAME2       2018-12-01         1      
   A125       NAME3       2018-12-01         1      
   [...]
   A123       NAME1       2018-12-02         2      
   A124       NAME2       2018-12-02         2      
   A125       NAME3       2018-12-02         2      
   [...]
   A123       NAME1       2018-12-03         3      
   A124       NAME2       2018-12-03         3     
   A125       NAME3       2018-12-03         3

我在这里改编了@johncappelletti的代码,但是我很难包含'd\u days\u passed'列,它基本上统计自开始日期以来的天数:

DECLARE @fromdate date = '2018-12-01'

SELECT #MyTable.*, B.D
FROM #MyTable
CROSS APPLY
    (SELECT TOP (DATEDIFF(DAY, @fromdate, DATEADD(Month, 9, @fromdate)) + 1) 
         D = CONVERT(date, DATEADD(DAY, -1 + ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), @fromdate))
     FROM master..spt_values n1) B

如果你有时间,
问题:如何调整代码,而不是将每个诊所从一个日期到另一个日期的每一天都包括在内,我想为每个诊所引入相同的周周期,例如,从周六到周日:

Clinic_code Clinic_name        D_start        D_end         Weeks_passed
-------------------------------------------------------------------------
   A123       NAME1           2018-12-02   2018-12-08             1      
   A124       NAME2           2018-12-02   2018-12-08             1      
   A125       NAME3           2018-12-02   2018-12-08             1      
   [...]
   A123       NAME1           2018-12-09   2018-12-15             2 
   A124       NAME2           2018-12-09   2018-12-15             2 
   A125       NAME3           2018-12-09   2018-12-15             2 
   [...]
   A123       NAME1           2018-12-16   2018-12-22             3
   A124       NAME2           2018-12-16   2018-12-22             3
   A125       NAME3           2018-12-16   2018-12-22             3
p1tboqfb

p1tboqfb1#

您只需使用窗口函数来获取最早的日期,然后 datediff() :

Select t.*, B.D,
       datediff(day, min(date) over (), date) + 1 as days_passed
From  #MyTable t Cross Apply
      (Select Top (DateDiff(DAY,@fromdate,DateAdd(Month,9,@fromdate))+1) 
                  D=convert(date,DateAdd(DAY,-1+Row_Number() Over (Order By (Select Null)),@fromdate))
       From  master..spt_values n1
      ) B;

这也应该持续几个星期。

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