为了实现您想要的目标，首先您需要知道如何在oracle中找到公共字符串开头：

with rws as ( 
  -- generate rows up to the length of the longest string 
  select rownum r from dual 
  connect by level <= (select max(length(str)) from strings) 
) 
select distinct s  
from ( 
  select str, max(subp) s  
  from ( 
    select str,  
           substr(str, 1, rws.r) subp 
    from   strings s1 
    cross join rws 
    where  r < length(str) 
    and    exists ( 
      -- check whether there's another string matching the first N chars 
      select * from strings s2 
      where  s1.str <> s2.str 
      and    substr(s1.str, 1, rws.r) = substr(s2.str, 1, rws.r) 
    ) 
  )  
  group by str 
)

取自https://livesql.oracle.com/apex/livesql/file/content_cc83zwpcpesedtadifosb1exi.html
当然，您需要将此应用于您的表。差异：
您将需要使用您的列
你需要按列分组