需要帮助生成几个月没有订单的空条目吗

slmsl1lt  于 2021-07-24  发布在  Java
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我必须创建显示表(tbl)中所有字段的输出,并创建一个额外的列来按月计算每个客户的累计总和(例如,如果一个客户在4月份有两次销售,那么新列将在两行上显示这些销售和任何以前的销售的总和)。我能做的就那么多。
我的问题是每个月为每个客户生成行,即使他们没有销售,但仍然让累计列正确显示上个月的累计金额。
所需输出:图片链接

  1. Customer_ID Order_ID Order_Date Order_Amt_Total_USD Month_ID Cum_Total_By_Month
  2. John 123 4/4/2019 30 Jun-19 120
  3. John 124 4/12/2019 90 Jun-19 120
  4. Mark null null null Jun-19 0
  5. Sally 150 4/20/2019 50 Jun-19 50
  6. John null null null Jul-19 120
  7. Mark 165 7/7/2019 80 Jul-19 170
  8. Mark 166 7/7/2019 90 Jul-19 170
  9. Sally 160 7/5/2019 75 Jul-19 125
  10. John null null null Aug-19 120
  11. Mark null null null Aug-19 170
  12. Sally null null null Aug-19 125

我将在下面列出代码,但这是一个链接,指向一个sql摆弄示例数据和两个查询我所处理的部分(在这个站点上的优秀人员的帮助下)。http://sqlfiddle.com/#!2011年1月15日
我可以使用第一个查询按客户和月份生成所需的累计运行总和。
我还可以生成一个基表,在第二个查询中为每个月的每个客户提供一个month\u id。
我需要帮助将这两种方法结合起来,以便在月份/客户没有任何销售额的情况下,使用空行生成所需的输出。
有什么想法吗?谢谢!

  1. -- Generates cumulative total by month by Customer, but only shows when they have a sale
  2. SELECT
  3. Customer_ID, Order_Date, order_id, Order_Amt_Total_USD,
  4. to_char(date_trunc('month', Order_Date), 'Mon YYYY') AS mon_text,
  5. (Select
  6. sum(Order_Amt_Total_USD)
  7. FROM tbl t2
  8. WHERE t2.Customer_ID = t.Customer_ID
  9. AND date_trunc('month', t2.Order_Date) <= t.Order_Date ) AS Cumulative
  10. FROM tbl t
  11. GROUP BY mon_text, Customer_ID, Order_Date, order_id, Order_Amt_Total_USD
  12. ORDER BY date_trunc('month', Order_Date), Customer_ID, Order_Date
  13. ;
  14. -- Generates Proper List of All Month IDs for each Customer from entered date through today
  15. WITH temp AS (
  16. SELECT date_trunc('month', Order_Date) AS mon_id
  17. FROM tbl
  18. )
  19. Select
  20. Customer_ID,
  21. to_char(mon_id, 'Mon YYYY') AS mon_text
  22. From tbl,
  23. generate_series('2015-01-01'::date, now(), interval '1 month') mon_id
  24. LEFT JOIN temp USING (mon_id)
  25. GROUP BY mon_id,Customer_ID
  26. ;
hs1ihplo

hs1ihplo1#

根据您的描述,可以将窗口函数与 generate_series() :

  1. SELECT c.Customer_ID, mon,
  2. SUM(Order_Amt_Total_USD) as month_total,
  3. SUM(SUM(Order_Amt_Total_USD)) OVER (PARTITION BY c.Customer_ID ORDER BY mon) as running_total
  4. FROM (SELECT DISTINCT Customer_Id FROM tbl) c CROSS JOIN
  5. generate_series('2015-01-01'::date, now(), interval '1 month') mon LEFT JOIN
  6. tbl t
  7. ON t.Customer_Id = c.customer_id and
  8. date_trunc('month', t.Order_Date) = mon
  9. GROUP BY c.Customer_ID, mon
  10. ORDER BY 1, 2;

这是一个sql小提琴。

qxgroojn

qxgroojn2#

下面的示例显示了如何使用partitionby来实现输出-
架构

  1. CREATE TABLE tbl (Order_ID varchar(10), Customer_ID varchar(10), Order_Date date, Order_Amt_Total_USD bigint);
  2. INSERT INTO tbl (Order_ID, Customer_ID, Order_Date, Order_Amt_Total_USD)
  3. VALUES
  4. ('100', 'qwe', '2015-08-04', 6),
  5. ('101', 'qwe', '2015-05-20', 7),
  6. ('102', 'qwe', '2015-04-08', 8),
  7. ('103', 'qwe', '2015-04-07', 9),
  8. ('109', 'aaa', '2015-04-28', 1),
  9. ('110', 'aaa', '2015-04-28', 2),
  10. ('111', 'aaa', '2015-05-19', 3),
  11. ('112', 'aaa', '2015-08-06', 4),
  12. ('113', 'aaa', '2015-08-27', 5),
  13. ('114', 'aaa', '2015-08-07', 6)

查询

  1. select Order_Date , Customer_ID, Order_Amt_Total_USD,
  2. sum(Order_Amt_Total_USD) over (partition by Customer_ID order by Order_Date) as cumulative
  3. from tbl;
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