我已经在编程新的几个月，我正在开发我的第一个正式项目。当我试图通过分配角色来创建用户时，遇到了这个问题。我有一个用户类，它有一个集合roles=newhashset<>（）。然后我有一个role类，它有一个字符串namerole，它与表的id相同。我使用insert将角色直接插入到db中。添加用户时出现以下异常：
事先谢谢你，我道歉，如果这将是琐碎的你，但我是新的编程。
javax.persistence.entitynotfoundexception:找不到id为string的com.work.portal.model.role
用户类

@Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
@Table(name = "user")
@ApiModel(description = "Details about the user")
public class User implements Serializable, UserDetails {
   @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String name;
    private String lastname;
    @ApiModelProperty(notes = "The user's email/username")
    @Column(name = "email", unique = true)
    private String username;
    private String password;
    @Type(type = "yes_no")
    private Boolean requestChangePassword = Boolean.FALSE;
    private Date dateCreated;
    private Date dateLastLogin;
    @Type(type = "yes_no")
    private Boolean enabled= Boolean.TRUE;
    @ManyToMany(fetch = FetchType.EAGER)
    @JoinTable(name = "user_role", joinColumns = @JoinColumn(name = "user_id", columnDefinition = "BINARY(16)"),
                inverseJoinColumns = @JoinColumn(name = "role_id", columnDefinition = "VARCHAR(16)"))
    private Set<Role> roles = new HashSet<>();
    public void addRole(Role role) {
        this.roles.add(role);

角色类

@Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
@Table(name = "role")
@ApiModel(description = "Details about the role")
public class Role implements Serializable {
    @Id
    @Column(columnDefinition = "VARCHAR(16)")
    private String name;
}

用户服务方法adduser

@Autowired
private RoleRepository roleRepository;
public User addUser(User user) {                                         
    if (!user.getUsername().equals("admin")) {                           
        user.addRole(roleRepository.findById("ROLE_ADMIN").get());       
    } else {                                                             
        user.addRole(roleRepository.findById("ROLE_PARTNER").get());     
    }                                                                    
    return userRepository.save(user);                                    
}

角色存储库

@Repository("roleRepository")
public interface RoleRepository extends JpaRepository<Role, String> {
}