我可以知道如何修改下面的sql查询,以便使用pivot table where()将结果转换为预期结果吗?对于monthyear=start date和end date selected by user?
sql查询:sql查询结果(图像)
预期结果:表(图像)
SELECT * FROM
(
SELECT WR.Work_Type,
LEFT(DATENAME(MONTH,WR.Request_Date),3)+' '+STR(YEAR(WR.Request_Date),4) AS MonthYear,
CONVERT(INT,STR(YEAR(WR.Request_Date),4)+REPLACE(STR(MONTH(WR.Request_Date),2),' ','0') ) AS MonthYearOrder,
COUNT(ISNULL(WR.Request_ID,0)) AS Total
FROM tblWork_Request WR
INNER JOIN vWorkTypeByPropertyLevel WT ON WR.CoID=WT.CoID AND WR.Work_Type=WT.Work_Type AND WT.IsWorkRequest=1
LEFT JOIN [UBERIQ_1.5_Property].[dbo].[tblProperty] P ON WR.Property_ID=P.Property_ID
WHERE WR.CoID='59' and WR.Property_ID='MCST001'
GROUP BY WR.Work_Type,LEFT(DATENAME(MONTH,WR.Request_Date),3)+' '+STR(YEAR(WR.Request_Date),4),
CONVERT(INT,STR(YEAR(WR.Request_Date),4)+REPLACE(STR(MONTH(WR.Request_Date),2),' ','0') )
) t
pivot (
SUM(Total)
FOR MonthYear IN ()
) as pivot_table
结果:-
Work_Type | MonthYear | MonthYearOrder | Total
----------------------------------------------------------
A.1 Problem Code 1 | Jun 2020 | 202006 | 3
AHU faulty | Nov 2020 | 202011 | 6
AirCondition | May 2020 | 202005 | 1
Exterior | Jun 2020 | 202006 | 2
预期结果:-
Work Type | Jan 2020 | Feb 2020 | Mar 2020 | Apr 2020 | May 2020 | Jun 2020 | Jun 2020 | Jul 2020 | Aug 2020 | Sep 2020 | Oct 2020 | Nov 2020 | Dec 2020 |
-----------------------------------------------------------------------------------------------------------------------------------------------------------
A.1 Problem Code 1 | 0 | 0 | 0 | 0 | 0 | 3 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
AHU Faulty | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 6 | 0 |
AirCondition | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
Exterior | 0 | 0 | 0 | 0 | 0 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
请告知。谢谢您。
1条答案
按热度按时间6yoyoihd1#
此查询的结果:http://sqlfiddle.com/#!18/96333/63