此代码来自建议的解决方案：https://asktom.oracle.com/pls/asktom/f?p=100：11:0:：：p11\问题号：9541646100346616701
我的问题是 'select * from table' 第二列是一个日期，这个例程按照我的ide会话（'dd-mon-yy'）中的显示写入它；
如何将日期列中的值报告给“yyyy-mm-dd”？

procedure clob_maker(p_query varchar2) is

      l_theCursor     integer default dbms_sql.open_cursor;
      l_columnValue   varchar2(4000);
      l_status        integer;
      l_descTbl       dbms_sql.desc_tab;
      l_colCnt        number;
      n number := 0;

      l_data clob;
  begin
      dbms_sql.parse(  l_theCursor,  p_query, dbms_sql.native );
      dbms_sql.describe_columns( l_theCursor, l_colCnt, l_descTbl );

      for i in 1 .. l_colCnt loop
          dbms_sql.define_column(l_theCursor, i, l_columnValue, 4000);
      end loop;

      l_status := dbms_sql.execute(l_theCursor);

      while ( dbms_sql.fetch_rows(l_theCursor) > 0 ) loop
          for i in 1 .. l_colCnt loop 
              dbms_sql.column_value( l_theCursor, i, l_columnValue );
              --dbms_output.put_line(l_columnValue);  --this puts every column on a separate line
                l_data := l_data || l_columnValue ||',';
          end loop;
            dbms_output.put_line(l_data);
          n := n + 1;
      end loop;
      --dbms_output.put_line(l_data);
  end  clob_maker;

clob_maker('select * from mlb_catcher_birthdays fetch first 10 rows only');