想知道是否有人能帮忙。
我试着把日期列中的值,天的值,分组成一个月,得到一个月收到的托盘总数的摘要。
在select/group语句中添加到\u char(conf\u date,'mm yyyy')时,我得到一个错误'ora-01722:无效数字'。
提前谢谢!
我当前的sql
with pallets_received as (
select a.comp_code,
a.cust_code,
a.rcpt_num,
to_char(a.rcpt_conf_date,'mm-dd-yyyy')conf_date,
sum(b.rcpt_loc_qty)/(c.item_qty_bkd_qty) pallets
from e_rcpt_h a
left join e_rcpt_d5D1 b
on a.comp_code=b.comp_code
and a.rcpt_num=b.rcpt_num
left join m_item_d1 c
on b.comp_code=c.comp_code
and b.cust_code=c.cust_code
and b.invt_lev1=c.item_code
where a.comp_code='T3'
and c.item_qty_bkd_lev_num=1
and a.cust_code='101029'
and a.flow_pros_code='CORE'
and trunc(a.rcpt_conf_date) >= to_date('02-01-2020','mm-dd-yyyy')
group by a.comp_code,
a.cust_code,
a.rcpt_num,
a.rcpt_conf_date,
c.item_qty_bkd_qty
order by conf_date
)
select comp_code,
cust_code,
conf_dateas month,
sum(ceil(pallets)) pallets
from pallets_received
group by comp_code,
cust_code,
conf_date
order by conf_date
table
comp_code | cust_code | conf_date | pallets
---------------------------------------------
T3 101029 03-06-2020 2
T3 101029 03-09-2020 8
C4 101029 04-05-2020 2
C4 101029 04-05-2020 8
我努力实现的产出
comp_code | cust_code | month | pallets
---------------------------------------------
T3 101029 03-2020 10
C4 101029 04-2020 10
1条答案
按热度按时间hwamh0ep1#
conf\u date只是字符串结果“to\u char(a.rcpt\u conf\u date,'mm-dd-yyyy')的别名,因此conf\u date实际上只是一个字符串。然而,在您的组中,您正在将其喂给\u char。这迫使oracle首先使用nls\ U date\格式的控制值来执行隐含的to\ U date。几乎可以保证返回错误。
(是的,您需要学习格式化代码。。为了你自己的理智,也为了其他人的理智。)