我正在扩展 IdentityUser , IdentityUserRole ，和 IdentityRole 这样地：

public class ApplicationUser : IdentityUser
{
    public string FullName { get; set; }

    public virtual ICollection<ApplicationIdentityUserRole> Roles { get; } = new List<ApplicationIdentityUserRole>();
}

public class ApplicationIdentityUserRole : IdentityUserRole<string>
{
    public virtual ApplicationUser User { get; set; }
    public virtual ApplicationRole Role { get; set; }
}

public class ApplicationRole : IdentityRole
    {
        public virtual ICollection<ApplicationIdentityUserRole> Roles { get; } = new List<ApplicationIdentityUserRole>();
    }

配置如下：

public class SmartAccountingSetUpContext : IdentityDbContext<ApplicationUser>
{
    public SmartAccountingSetUpContext(DbContextOptions<SmartAccountingSetUpContext> options)
        : base(options)
    {

    }

    public DbSet<ApplicationUser> Users { get; set; }

    protected override void OnModelCreating(ModelBuilder builder)
    {
        base.OnModelCreating(builder);

        builder.Ignore<RegistrationViewModel>();
        // Customize the ASP.NET Identity model and override the defaults if needed.
        // For example, you can rename the ASP.NET Identity table names and more.
        // Add your customizations after calling base.OnModelCreating(builder);            
        builder.Entity<ApplicationUser>().ToTable("AspNetUsers");
        builder.Entity<ApplicationIdentityUserRole>().ToTable("AspNetUserRoles");
        builder.Entity<ApplicationRole>().ToTable("AspNetRoles");           

        builder.Entity<ApplicationIdentityUserRole>()
                    .HasOne(p => p.User)
                    .WithMany(b => b.Roles)
                    .HasForeignKey(p => p.UserId);

        builder.Entity<ApplicationIdentityUserRole>()
            .HasOne(x => x.Role)
            .WithMany(x => x.Roles)
            .HasForeignKey(p => p.RoleId);
    }
}

我一直在想：

"Invalid column name 'Discriminator'.\r\nInvalid column name 'Discriminator'.\r\nInvalid column name 'Discriminator'.\r\nInvalid column name 'Discriminator'."

我知道如果您有派生类，那么您必须在onmodelcreating方法中指定hasdiscriminitor。但是identityuser、identityuserrole和identityrole不是抽象类。
我该怎么过去？