大家好，我被sql中的这个问题困住了：mysql总是在第4行给我语法错误，但我真的不知道它可能是什么

mhd8tkvw 于 2021-08-13 发布在 Java

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代码如下：

CREATE TRIGGER inserisci_richiesta_noID AFTER INSERT ON Richiesta
FOR EACH ROW
BEGIN    
    IF (NEW.ID_Cliente == NULL AND (NEW.Email NOT IN (SELECT Email FROM Utente))) THEN
        INSERT INTO Utente(ID, Nome, Cognome, Email, Telefono, ID_Livello_accesso)
        VALUES (NULL, 'Generato', 'Automaticamnete', NEW.Email, NEW.Telefono, 1);
        UPDATE Richiesta
        SET ID_Cliente = (SELECT ID FROM Cliente WHERE Email = :NEW.Email);
    ELSE NEW.ID_Cliente == NULL AND NEW.Email IN (SELECT Email FROM Utente;) THEN
        UPDATE Richiesta
        SET ID_Cliente = (SELECT ID FROM Cliente WHERE Email = NEW.Email);
    END IF;
END;

它给了我这个错误：
1064-您的sql语法有错误；请检查与您的mysql服务器版本对应的手册，以获得正确的语法，以便在“==null”附近使用（new.email not in（select email from utente）），然后在第4行的u'中插入

sql mysql triggers

来源：https://stackoverflow.com/questions/62129712/hi-to-everyone-im-stuck-with-this-problem-in-sql-mysql-gives-me-always-syntax

1条答案

按热度按时间

zyfwsgd61#

这是密码

DELIMITER $$

CREATE TRIGGER inserisci_richiesta_noID AFTER INSERT ON Richiesta
FOR EACH ROW
BEGIN    
 IF (NEW.ID_Cliente IS NULL AND (NEW.Email NOT IN (SELECT Email FROM Utente))) THEN
    INSERT INTO Utente(ID, Nome, Cognome, Email, Telefono, ID_Livello_accesso)
    VALUES (NULL, 'Generato', 'Automaticamnete', NEW.Email, NEW.Telefono, 1)
    UPDATE Richiesta
    SET ID_Cliente = (SELECT ID FROM Cliente WHERE Email = NEW.Email);
ELSE IF (NEW.ID_Cliente IS NULL AND NEW.Email IN (SELECT Email FROM Utente)) THEN
    UPDATE Richiesta
    SET ID_Cliente = (SELECT ID FROM Cliente WHERE Email = NEW.Email);
END IF;
END$$

 DELIMITER ;

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大家好，我被sql中的这个问题困住了：mysql总是在第4行给我语法错误，但我真的不知道它可能是什么

1条答案

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