sql—检查“employee”的“entry”数目,以及“activity”是否与最后3个“entry”相同

0wi1tuuw  于 2021-08-13  发布在  Java
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我想运行一个查询,在那里我想找到 TICKETS 相同 EMPLOYEE 至少记录3次 ENTRY 但在这方面没有任何进展 TICKET . 不幸的是,我在以下方面遇到了问题:
如何检查进度
TICKET ENTRYACTIVITY_ID 定义的活动是

INSERT INTO ACTIVITY(ACTIVITY_ID,ACTIVITY_NAME) VALUES ('RGSTR','REGISTER')
INSERT INTO ACTIVITY(ACTIVITY_ID,ACTIVITY_NAME) VALUES ('ASST','ASSISTANCE')
INSERT INTO ACTIVITY(ACTIVITY_ID,ACTIVITY_NAME) VALUES ('ADVTS','ADVERTISEMENT')
INSERT INTO ACTIVITY(ACTIVITY_ID,ACTIVITY_NAME) VALUES ('SALE','SALE')
INSERT INTO ACTIVITY(ACTIVITY_ID,ACTIVITY_NAME) VALUES ('RFND','REFUND')
INSERT INTO ACTIVITY(ACTIVITY_ID,ACTIVITY_NAME) VALUES ('EXTND','EXTEND')

到目前为止我所做的是:

SELECT
  TICKET.TICKET_ID,
  EMPLOYEE.LAST_NAME,
  COUNT(TICKET.TICKET_ID) AS NUMBER
FROM ENTRY
JOIN EMPLOYEE ON ENTRY.EMPLOYEE_ID = EMPLOYEE.EMPLOYEE_ID
JOIN TICKET ON ENTRY.TICKET_ID = TICKET.TICKET_ID
GROUP BY TICKET.TICKET_ID, EMPLOYEE.LAST_NAME
HAVING COUNT(ENTRY.ACTIVITY_ID) >= 3

我选择了一些列来查看输出是什么(当我有一个 SELECT COUNT(*) 输出是两行,两行都是3行。这是数钱 ENTRY 每一张票,但我要数 TICKET 大于等于3的 ENTRY 以及上述额外财产)

ID  LAST_NAME   NUMBER  No Column Name
5   LaBeouf      3        3
6   Musk         3        3

这个输出没有错,因为我在 ENTRY 下表类似,但我基本上想得到这个输出中的行数,但做不到。

--more entries above
--.
--.
INSERT INTO ENTRY(ACTIVITY_ID,EMPLOYEE_ID,TICKET_ID,DATE,DESCRIPTION)
VALUES ('RGSTR',6,5,'2020-5-29','Didnt do anything')
INSERT INTO ENTRY(ACTIVITY_ID,EMPLOYEE_ID,TICKET_ID,DATE,DESCRIPTION)
VALUES ('RGSTR',6,5,'2020-5-29','Didnt do anything')
INSERT INTO ENTRY(ACTIVITY_ID,EMPLOYEE_ID,TICKET_ID,DATE,DESCRIPTION)
VALUES ('RGSTR',6,5,'2020-5-29','Didnt do anything')

INSERT INTO ENTRY(ACTIVITY_ID,EMPLOYEE_ID,TICKET_ID,DATE,DESCRIPTION)
VALUES ('RGSTR',2,6,'2020-5-29','Didnt do anything')
INSERT INTO ENTRY(ACTIVITY_ID,EMPLOYEE_ID,TICKET_ID,DATE,DESCRIPTION)
VALUES ('RGSTR',2,6,'2020-5-29','Didnt do anything')
INSERT INTO ENTRY(ACTIVITY_ID,EMPLOYEE_ID,TICKET_ID,DATE,DESCRIPTION)
VALUES ('RGSTR',2,6,'2020-5-29','Didnt do anything')

最后,我自己设计了数据库作为项目的一部分这里是er图,如果它能帮助你更好地理解。
感谢所有花时间帮忙的人
edit:解决了这个问题,我基本上计算了上面输出中的行数,并添加了一个where语句,它将只计算 ENTRY ies与 ACTIVITY_ID='RGSTR' ```
SELECT COUNT() AS # FROM
(SELECT
TICKET.TICKET_ID,
EMPLOYEE.LAST_NAME,COUNT(
) AS NUMBER FROM ACTIVITY
INNER JOIN ENTRY ON ACTIVITY.ACTIVITY_ID = ENTRY.ACTIVITY_ID
INNER JOIN EMPLOYEE ON ENTRY.EMPLOYEE_ID = EMPLOYEE.EMPLOYEE_ID
INNER JOIN TICKET ON ENTRY.TICKET_ID = TICKET.TICKET_ID
WHERE ENTRY.ACTIVITY_ID = 'RGSTR'
--added above line since we are checking
--for tickets that an employe worked >=3 times but couldn't resolve
GROUP BY TICKET.TICKET_ID,EMPLOYEE.LAST_NAME
HAVING COUNT(ENTRY.ACTIVITY_ID) >= 3) c

我应该删除这个线程吗?

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