创建列,其中根据其他列值的条件值对其他列求和?

ipakzgxi  于 2021-08-13  发布在  Java
关注(0)|答案(1)|浏览(310)

我需要创建列,其中根据其他列值的条件对其他列求和。要求如下。
我有下表:

key code1  code2 code3 code4 value1 value2 value3 value4 
0    101   101   101   101   1000    1000  1000   1000    
1    101   101   101   201   1000    1000  1000   1000    
2    101   101   201   201   1000    1000  1000   1000    
3    101   201   201   201   1000    1000  1000   1000    
4    101   201   201   301   1000    1000  1000   1000    
5    101   201   301   301   1000    1000  1000   1000    
6    101   301   301   301   1000    1000  1000   1000    
7    101   101   101   301   1000    1000  1000   1000    
8    101   201   301   0     1000    1000  1000   0       
9    101   301   0     0     1000    1000  0      0       
....

考虑到列代码(code1,code2,code3,code4),我需要创建一个列来对列值(value1,value2,value3,value4)求和。结果应该是这样的:

key  code1 code2 code3 code4 value1 value2 value3 value4 sum_code_101 sum_code_201 sum_code_301
0    101   101   101   101   1000    1000  1000   1000     4000           0           0
1    101   101   101   201   1000    1000  1000   1000     3000           1000        0
2    101   101   201   201   1000    1000  1000   1000     2000           2000        0
3    101   201   201   201   1000    1000  1000   1000     1000           3000        0
4    101   201   201   301   1000    1000  1000   1000     1000           2000        1000
5    101   201   301   301   1000    1000  1000   1000     1000           1000        2000
6    101   301   301   301   1000    1000  1000   1000     1000           0           3000
7    101   101   101   301   1000    1000  1000   1000     3000           0           1000
8    101   201   301   0     1000    1000  1000   0        1000           1000        1000
9    101   301   0     0     1000    1000  0      0        1000           0           1000

由于实际表有25个不同的代码(101、201、301…),我需要创建25列来求它们的值之和。
任何帮助都将不胜感激。

xkftehaa

xkftehaa1#

你可以用 case 表达:

select
    t.*,
    case when code1 = 101 then value1 else 0 end
        + case when code2 = 101 then value2 else 0 end
        + case when code3 = 101 then value3 else 0 end
        + case when code4 = 101 then value4 else 0 end
        as sum_code_101,
    case when code1 = 201 then value1 else 0 end
        + case when code2 = 201 then value2 else 0 end
        + case when code3 = 201 then value3 else 0 end
        + case when code4 = 201 then value4 else 0 end
        as sum_code_201,
    case when code1 = 301 then value1 else 0 end
        + case when code2 = 301 then value2 else 0 end
        + case when code3 = 301 then value3 else 0 end
        + case when code4 = 301 then value4 else 0 end
        as sum_code_301
from mytable t

通过取消对行的分隔,可以稍微缩短语法 cross apply ,然后使用条件聚合:

select
    t.*,
    s.*
from mytable t
outer apply (
    select 
        sum(case when code = 101 then val else 0 end) sum_code_101,
        sum(case when code = 201 then val else 0 end) sum_code_201,
        sum(case when code = 301 then val else 0 end) sum_code_301,
        sum(case when code = 401 then val else 0 end) sum_code_401
    from (values 
        (t.code1, t.value1), 
        (t.code2, t.value2), 
        (t.code3, t.value3), 
        (t.code4, t.value4)
    ) as x(code, val)
)  s

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