我将sequelize与sqlite一起使用，我想

SELECT DISTINCT * 
FROM users AS u 
    LEFT JOIN months AS m ON u.id = m.userid 
    LEFT JOIN worktimerecords AS w on m.id = w.monthid 
WHERE w.projectid = ${id}

…但是使用模型，这是可能的吗？
我试过了

User.findAll({
        include: [
          {
            model: Month,
            include: [
              {
                model: WorkTimeRecord,
                where: { projectId: id },
              },
            ],
          },
        ],
      })

但是where不起作用，并且返回所有项目的用户，我只希望返回一个项目的用户。