@艾玛
下面是一些可能对您有帮助的代码。我们的想法是尝试模仿或模仿本摘录中的风格和最佳实践：

import java.util.Scanner;

public class ArrayFiller {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

            System.out.println("How many elements do you want to enter");
            int input_element_count = sc.nextInt(); //Number of how many elements the user want to enter
            int element_count = input_element_count;

        int[] array = new int[element_count]; //An array with all the values
        enter_elements_of_array(array, element_count, sc);
        double average = averageCalculator(array, element_count);
        printArray(array);
        System.out.println("The average of the entered numbers is " + average);

    }

    public static void printArray(int[] array) {

        System.out.print("The array you entered is : [");
        for (int element : array) {
            System.out.print(" " + element + " ");
        }
        System.out.print("]" + "\n");
    }

    public static void enter_elements_of_array( int[] array, int element_count, Scanner sc) { 

            for (int i = 0; i < element_count; i++) { //Add all the inputs in the array
                System.out.println("Please enter element " + (i+1) + " of " + element_count + ":");
                array[i] = sc.nextInt();
            }
    }

        public static double averageCalculator ( int[] array, int element_count){
            double average; // The average
            double sum = 0; // The total sum of the inputs

            for (int i = 0; i < element_count; i++) {
                sum = sum + array[i];
            }
                average = sum / element_count;

            return average;
        }

        //Count the occurence of inputs that only occur once
        public static int countOccurence(int[] array) { 
            int count = 0;
            // algorithm for counting elements with cardinality of 1
            return count;
        }

}

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