我已经看到这类问题已经得到了回答,但是每个答案都有点模糊,或者有一些交叉兼容性问题,或者太超出了我的理解。那么有没有人可以给我一个最新的、完整的,清楚(显示并解释所有涉及的步骤)答案?我不想让鼠标在窗口外时圆圈变大。我没有使用jquery(在许多答案中都有)。我应该使用它吗?有没有办法用纯javascript实现这一点?感谢您的帮助,如果我的代码有点多余,请原谅:)
var canvas = document.querySelector("canvas");
var c = canvas.getContext('2d');
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
var mouse = {
x: undefined,
y: undefined
}
window.addEventListener("mousemove", function(event){
mouse.x = event.x;
mouse.y = event.y;
})
window.addEventListener("resize", function(){
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
})
var colorArray = [
"#6CC61D",
"#E05132",
"#278E83",
"#A633D4"
]
function Circle(x,y,dx,dy,radius){
this.x = x;
this.y = y;
this.dx = dx;
this.dy = dy;
this.radius = radius;
this.color = colorArray[Math.floor(Math.random() * colorArray.length)];
this.draw = function(){
c.beginPath();
c.arc(this.x,this.y,this.radius,0,Math.PI*2,false);
c.fillStyle = this.color;
c.fill()
}
this.update = function(){
if (this.x + this.radius>window.innerWidth || this.x -this.radius<0){
this.dx = - this.dx;}
if (this.y + this.radius > window.innerHeight || this.y - this.radius < 0) {
this.dy = - this.dy;
}
if (mouse.x - this.x < 50 && mouse.x - this.x > - 50 && mouse.y - this.y < 50 && mouse.y - this.y > - 50 && this.radius<50 ){
this.radius += 1;
}
else if(this.radius>2){
this.radius -= 1;
}
this.x += this.dx;
this.y += this.dy;
this.draw();
}
}
var circleArray = [];
for (var i = 0; i < 600; i++) {
var x = Math.random() * (window.innerWidth - radius * 2) + radius;
var y = Math.random() * (window.innerHeight - radius * 2) + radius;
var dy = (Math.random() - 0.5) * 8;
var dx = (Math.random() - 0.5) * 8;
var radius = 30;
circleArray.push(new Circle(x, y, dx, dy, radius));
}
function animate(){
requestAnimationFrame(animate);
c.clearRect(0,0,window.innerWidth,window.innerHeight);
for (var i = 0;i < circleArray.length;i++){
circleArray[i].update()
}
circle.update();
}
animate();
暂无答案!
目前还没有任何答案,快来回答吧!