我正在尝试编写一个程序,它将在一个循环双链接列表中前进一定的次数,并在同一个列表中后退一定的次数。如果两种方法都以相同的数字结束,则该数字为“值得”,并从列表中删除。如果这些方法不在列表中的同一个元素上结束,那么它们就没有价值,也会从列表中删除。我已经多次编写了前进和后退的方法,但是一旦元素被认为是有价值的或不值得的,我就很难删除它们。这就是我目前所拥有的。任何帮助都将不胜感激。
import java.util.Arrays;
public class LinkedList {
private Node head;
private Node end;
LinkedList(){
head = end = null;
}
public void addAtStart(int x){
if (head == null) {
Node new_node = new Node(x);
new_node.data = x;
new_node.next = new_node.prev = new_node;
head = new_node;
} else if (head != null) {
Node last = (head).prev;
Node new_node = new Node(x);
new_node.data = x;
new_node.next = head;
(head).prev = new_node;
new_node.prev = last;
last.next = new_node;
}
}
public void printOutput(int N, int k, int m){
System.out.println("Output" + "\n" + "------" + "\n");
printCandidates(N,k,m);
}
public void printCandidates(int N, int k, int m){
int unworthy[] = new int[N];
int worthy[] = new int[N];
int count = 0;
int run = 0;
Node temp = head;
do {
if (forwards(k) == backwards(m)){ // puts in worthy list and deletes from linked list
worthy[count] = forwards(k);
count += 1;
System.out.println("hello");
deleteElement(forwards(k));
} else if (forwards(k) != backwards(m)){ //put in unworthy list and delete from linked list
unworthy[run] = forwards(k);
unworthy[run+1] = backwards(m);
run += 2;
System.out.println("goodbye");
deleteElement(forwards(k));
deleteElement(backwards(m));
}
} while (temp != null);
System.out.println("Removed candidates from being elected");
System.out.println(Arrays.toString(unworthy));
System.out.println("Worthy candidates");
System.out.println(Arrays.toString(worthy));
}
int forwards(int k){
int run = 0;
int x = 0;
Node temp = head;
while (temp.next != head){
if(run == (k)){
x = temp.data;
}
temp = temp.next;
run += 1;
}
return x;
}
int backwards(int m){
int run = 0;
int x = 0;
Node temp = head;
Node last = head.prev;
temp = last;
while (temp.next != head){
if(run == (m)){
x = temp.data;
}
temp = temp.next;
run += 1;
}
return x;
}
public void deleteElement(int elementToBeDeleted){
Node temp = head;
while (temp.next != head){
if(temp.data == elementToBeDeleted){
temp.setNext(temp.next);
}
temp = temp.next;
}
}
这是我的司机:
public class Program2 {
public static void main(String[] args) {
LinkedList ll = new LinkedList();
for (int i = 1; i < 11; i++){
ll.addAtStart(i);
}
int N = 10;
int k = 4;
int m = 3;
System.out.println("N = " + N + ", " + "k = " + k + ", " + "m = " + m + "\n");
ll.printOutput(N,k,m);
}
}
这是我的节点类:
public class Node {
public int data;
public Node next;
public Node prev;
// Constructor to intialize/fill data
public Node(int data){
this.data = data;
}
// set the address of next node
public void setNext(Node temp) {
this.next = temp;
}
// get the address of next node
public Node getNext(){
return this.next;
}
public Node getPrev(){
return this.prev;
}
public void setPrev(Node temp) {
this.prev = temp;
}
// to get data of current node
public int getData(){
return this.data;
}
}
编辑:作为这个练习的一部分,我需要自己编写这个类,因此我需要实现自己的linkedlist。
暂无答案!
目前还没有任何答案,快来回答吧!