fastjson 1.2.47 version parse string "9999-12-31" error

oxiaedzo 于 2021-11-27 发布在 Java

关注(0)|答案(2)|浏览(446)

well , when I pasre string "9999-12-31" to Date ,fastjson take me a error:

com.alibaba.fastjson.JSONException: For input string: "9999-12-31"
at com.alibaba.fastjson.parser.DefaultJSONParser.parseObject(DefaultJSONParser.java:665)

What should I do ? I user annotation so I don't want to use JSON.DEFFAULT_DATE_FORMAT = "yyyy-MM-dd";

fastjson

来源：https://github.com/alibaba/fastjson/issues/1920

2条答案

按热度按时间

xlpyo6sf1#

haha , use @JSONField(format = "yyyy-MM-dd") can make it work

赞(0）回复(0）举报 2021-11-27

pkwftd7m2#

最新版本1.2.59，已经解决

赞(0）回复(0）举报 2021-11-27

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fastjson 1.2.47 version parse string "9999-12-31" error

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