您需要使用Java脚本的Filter方法来执行此操作。

以下是代码片段/解决方案：

let listOfObjects = [ 
  {field1 : 'value1',  field2 : 'value2', field3 : 'value3'}, 
  {field1 : 'value12',  field2 : 'value21', field3 : 'value31'}, 
  {field1 : 'value13',  field2 : 'value22', field3 : 'value32'}, 
  {field1 : 'value14',  field2 : 'value23', field3 : 'value33'}, 
  {field1 : 'value1',  field2 : 'value24', field3 : 'value34'}
];

console.log(`List of objects: `, listOfObjects)

let vList = listOfObjects.filter(x => listOfObjects[0].field1 === x.field1)

console.log(`Here is the Expected Solution:`); 

// field1 of first object matches with the field1 of last object in the list of objects. So, two objects are returned in the result.

console.log(vList)

使用直接查询从MongoDB本身过滤掉这些对象。这比检索所有MongoDB文档然后使用Java脚本过滤器更高效。

let docs = await Model.find({'ModelName.field1' : value1});