实现：在Service1中，将在方法transerValue中的service2中返回值，但当稍后调用CalledLaterMethod时，但当我尝试访问CalledLaterMethod中的transerValue时，它为空。有没有可能将值存储在transerValue中，并等待CalledLaterMethod被调用并获得该值？对于任何解决方案，请让我知道
@Data
@AllArgsConstructor
@NoArgsConstructor
@Builder
public class Class1{
private String param1;
private String param2;
}@Data
@AllArgsConstructor
@NoArgsConstructor
@Builder
public class Class2{
private String param4;
private String param5;
}@Slf4j
@Service
public class Service1{
// with method for validationString
public Class1 validationString(String val1, String val2){
String present = "PRESENT";
String empty = "EMPTY";
String param1Transfer = "";
String param2Transfer = "";
if(val1.isEmpty()) param1Transfer = empty;
else param1Transfer = present;
if(val2.isEmpty()) param2Transfer = empty;
else param2Transfer = present;
Class1 class1 = Class1.builder()
.param1(param1Transfer)
.param2(param2Transfer)
.build();
return Service2.transerValue(class1);
}
}@Slf4j
@Service
public class Service2{
public static Class1 transerValue(Class1 class1){
//log will work
log.info("Well this data show ={}",class1 );
return class1;
}
//this method CalledLaterMethod will be called later and i must get the value being transfer in transerValue
// and must not change the parameter of CalledLaterMethod
public static Class2 CalledLaterMethod(OtherClass1 other1,OtherClass other2 ){
// i tried
//this is null
Class1 class1 = new Class1();
Class1 classClone = transerValue(class1)
log.info(classClone);
//trying to do
Class2 class2 = Class2.builder.
.param4(classClone.getParam1)
.param5(classClone.getParam2)
build();
return class2;
}
}
1条答案
按热度按时间aor9mmx11#
您将始终得到NULL，因为您没有在CalledLaterMethod中的Class1中设置任何值，在那个类中，您只示例化对象Class1而不设置该对象中的值，除非您在CalledLaterMethod中传递了值Class1 from参数。我假设OtherClass1是要传递的Class1对象，如果不想更改CalledLaterMethod中的参数，可以这样做