我刚刚开始使用Spring Boot，并且我正在使用默认的存储库API来检索json形式的数据库数据。我已将@ManyToOne关系添加到我的Song and Artist实体。
但现在我没有从服务器获得json响应中的Artist对象，我也不清楚如何才能在不错过PagingAndSorting存储库的分页函数的情况下包括它。
我正在使用Spring-data-rest-JPA。
我现在的回应是：

"_embedded": {
    "songs": [
      {
        "id": 1,
        "title": "SongTitle",
        "genre": "Rap",
        "length": 500,
        "_links": {
          "self": {
            "href": "http://localhost:8080/api/songs/1"
          },
          "song": {
            "href": "http://localhost:8080/api/songs/1"
          },
          "artist": {
            "href": "http://localhost:8080/api/songs/1/artist"
          }
        }
      }
    ]
  },
  "_links": {
    "first": {
      "href": "http://localhost:8080/api/songs?page=0&size=1"
    },
    "self": {
      "href": "http://localhost:8080/api/songs?size=1"
    },
    "next": {
      "href": "http://localhost:8080/api/songs?page=1&size=1"
    },
    "last": {
      "href": "http://localhost:8080/api/songs?page=19&size=1"
    },
    "profile": {
      "href": "http://localhost:8080/api/profile/songs"
    }
  },
  "page": {
    "size": 1,
    "totalElements": 20,
    "totalPages": 20,
    "number": 0
  }
}

但我更希望是这样的：

"_embedded": {
    "songs": [
      {
        "id": 1,
        "title": "SongTitle",
        "genre": "Rap",
        "length": 500,
        "artist": {
           "id": 1,
           "name": "Artistname"
        }
        "_links": {
          "self": {
            "href": "http://localhost:8080/api/songs/1"
          },
          "song": {
            "href": "http://localhost:8080/api/songs/1"
          },
          "artist": {
            "href": "http://localhost:8080/api/songs/1/artist"
          }
        }
      }
    ]
  },
  "_links": {
    "first": {
      "href": "http://localhost:8080/api/songs?page=0&size=1"
    },
    "self": {
      "href": "http://localhost:8080/api/songs?size=1"
    },
    "next": {
      "href": "http://localhost:8080/api/songs?page=1&size=1"
    },
    "last": {
      "href": "http://localhost:8080/api/songs?page=19&size=1"
    },
    "profile": {
      "href": "http://localhost:8080/api/profile/songs"
    }
  },
  "page": {
    "size": 1,
    "totalElements": 20,
    "totalPages": 20,
    "number": 0
  }
}

Song.java

@Getter
@Setter
@Entity
@Table(name = "song")
public class Song {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false, unique = true)
    private Long id;

    @NotNull
    @NotBlank(message = "The song has to have a title")
    private String title;

    @NotNull
    @NotBlank(message = "The song has to have a genre")
    private String genre;

    @NotNull
    @Min(value = 1, message = "The song has to have a song length in seconds")
    private int length;

    @ManyToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = "artist_id", referencedColumnName = "id")
    private Artist artist;

   /* @Version
    private long version;*/

    public Song() {
    }

    public Song(String title, Artist artist, String genre, int length) {
        this.title = title;
        this.artist = artist;
        this.genre = genre;
        this.length = length;
    }

    public void setArtist(Artist artist) {
        this.artist = artist;
    }

    public Artist getArtist() {
        return artist;
    }

}

Artist.java

@Getter
@Setter
@Entity
@Table(name = "artist")
public class Artist {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false)
    private Long id;

    @NotNull
    @NotBlank(message = "The artist has to have a name")
    private String name;

    @JsonIgnore
    @OneToMany(mappedBy = "artist")
    private List<Song> songs;

    public Artist() {
    }

    public Artist(String name) {
        this.name = name;
    }

出于测试的目的，我在我的SongController中编写了一个方法：

@GetMapping
    List<Song> getSongs() {
        return songRepository.findAll();
    }

结果包括Artist对象，但不会对其进行任何分页。我怎么能把它包括进去呢？
JSON结果：

[
{
    "id": 1,
    "title": "SongTitle",
    "genre": "Rap",
    "length": 500,
    "artist": {
      "id": 1,
      "name": "ArtistName"
    }
  }
]