我正在尝试创建一个函数来更新名为customers的数据库中的每个客户(lastEmailed列),并且我已经多次尝试使用不同的查询输入和执行方法(更新,批更新等),我没有运气。这是我的切碎/注解代码看起来像,在混乱之后。任何建议都将非常感谢,谢谢!还有,输入样式的格式为2014-12-09 14:20:47(日期时间)。**这是一个命名参数JdbcTemplate。
这特别指的是updateTime函数,我只是包含了DAO的其余部分以提供帮助我希望在每次调用该函数时,仅使用lastEmailed的相同值来更新每个客户。
@Repository // creates the bean
public class CustomerDAO {
@Autowired
private NamedParameterJdbcTemplate jdbcTemplate;
private RowMapper<Customer> rowMapper = new RowMapper<Customer>() {
@Override
public Customer mapRow(ResultSet resultSet, int index) throws SQLException {
Customer customer = new Customer();
customer.setCustomerNumber(resultSet.getString("id"));
customer.setFirstName(resultSet.getString("fName"));
customer.setLastName(resultSet.getString("lName"));
customer.setEmail(resultSet.getString("email"));
customer.setStreet(resultSet.getString("street"));
customer.setCity(resultSet.getString("city"));
customer.setState(resultSet.getString("state"));
customer.setZip(resultSet.getString("zip"));
//Map Customer Fields Here
return customer;
}
};
public List<Customer> getCustomerList(){
String sql = "SELECT * FROM CUSTOMERS";
List<Customer> customerList =this.jdbcTemplate.query(sql, rowMapper);
return customerList;
}
//**in another class?
// public String toString(){
// List<Customer> temp = this.getCustomerList();
//
// }
public void saveCustomer(Customer customer) {
String sql = "INSERT INTO CUSTOMERS " +
"(id, lname, fname, email, street,city, state,zip) VALUES (:id, :lname, :fname, :email, " +
":street, :city, :state, :zip)";
Map<String, Object> parameters = new HashMap<String, Object>();
parameters.put("id", customer.getCustomerNumber());
parameters.put("lname", customer.getLastName());
parameters.put("fname", customer.getFirstName());
parameters.put("email", customer.getEmail());
parameters.put("street", customer.getStreet());
parameters.put("city", customer.getCity());
parameters.put("state", customer.getState());
parameters.put("zip", customer.getZip());
this.jdbcTemplate.update(sql, parameters);
}
public void updateTime(String timeSent){
String query = "UPDATE customers SET lastEmailed ='" + timeSent+"'";
// String query = "UPDATE customers SET lastEmailed = ?";
// String query = "INSERT INTO CUSTOMERS "
// this.jdbcTemplate.
// this.jdbcTemplate.executeppr
// this.jdbcTemplate.update
// jdbcTemplate.update("UPDATE customers SET lastEmailed=?",timeSent);
// SqlParameterSource [] parameterSource = SqlParameterSourceUtils.createBatch(this.getCustomerList().toArray());
// this.jdbcTemplate.batchUpdate("INSERT INTO CUSTOMERS (id,lastEmailed) VALUES (:customerNumber, " +timeSent + ")", parameterSource);
}
}
1条答案
按热度按时间2wnc66cl1#
我真不敢相信我竟然忽略了这一点,我在以前的一个函数中几乎就有了它,但是我没有意识到我只需要在map中放入一个值。感谢大家花时间看我的代码!