下面是返回的示例json

[
"id":
[
    {
        "reports":
            [
                {
                    "metadata":
                        {
                            "materialName" : "materialName1"
                            "materialType" : "materialType1"    
                        },
                        "xvalue": null,
                        "yvalue": null,
                },
                {
                    "metadata":
                        {
                            "materialName" : "materialName2"
                            "materialType" : "materialType2"    
                        },
                        "xvalue": null,
                        "yvalue": null,
                },
            ],
            "someValue" : "someValue1"
            "id" : "id1"
    },
    "reports":
            [
                {
                    "metadata":
                        {
                            "materialName" : "materialName3"
                            "materialType" : "materialType3"    
                        },
                        "xvalue": null,
                        "yvalue": null,
                },
                {
                    "metadata":
                        {
                            "materialName" : "materialName4"
                            "materialType" : "materialType4"    
                        },
                        "xvalue": null,
                        "yvalue": null,
                },
            ],
            "someValue" : "someValue1"
            "id" : "id2"
  ]

]
我在JMeter的Json路径提取器中有以下Json表达式

$.data[0].materials[?(@.id)].reports[*].metadata['materialName','materialType']

对于json数组中的每个'id'，上述表达式返回如下所示

materialName1, materialType1

materialName2, materialType2

materialName3, materialType3

materialName4, materialType4

但我希望提取“id”的值沿着“materialName”和“materialType”，如下所述

id1, materialName1, materialType1

id1, materialName2, materialType2

id2, materialName3, materialType3

id2, materialName4, materialType4

等等。
请帮帮我。
谢谢你，杰丁