我需要一个帮助grep一个文件，其中有大量的数据。我有一个文件与下面的行：

random line with hashcode 1
This file is use for some analysis
Analysis code is <01234>
This is line after analysis

This is second test line
This file is use for some analysis
Analysis code is <01234>
This is line after analysis

Some data to be here as well 
This file is use for some analysis
Analysis code is <01267>
This is line after analysis

我想只打印那些有字符串“分析代码”与值“01234”的行，并打印它之前和之后的所有行。我试图得到解决方案的一半，但需要完整的逻辑。

egrep -i "Analysis code" c.txt |
grep -i 01234 |
awk -F "<" '{print $2}' |
awk -F ">" '{print $1}' |
uniq > am.txt
while read line ; do
    echo $line
    awk "/$line/,/$^/" c.txt
done <am.txt

在这之后，我只从具有分析代码的行开始得到输出。
我想打印匹配字符串之前的所有行，直到空行出现在顶部：

random line with hashcode 1
This file is use for some analysis
Analysis code is <01234>
This is line after analysis

This is second test line
This file is use for some analysis
Analysis code is <01234>
This is line after analysis