雨燕3

let statusItem = NSStatusBar.system().statusItem(withLength: NSVariableStatusItemLength)

if let button = statusItem.button {
    button.action = #selector(self.statusBarButtonClicked(sender:))
    button.sendAction(on: [.leftMouseUp, .rightMouseUp])
}

func statusBarButtonClicked(sender: NSStatusBarButton) {
    let event = NSApp.currentEvent!

    if event.type == NSEventType.rightMouseUp {
        print("Right click")
    } else {
        print("Left click")
    }
}

雨燕4

let statusItem = NSStatusBar.system.statusItem(withLength: NSStatusItem.variableLength)

if let button = statusItem.button {
    button.action = #selector(self.statusBarButtonClicked(_:))
    button.sendAction(on: [.leftMouseUp, .rightMouseUp])
}

func statusBarButtonClicked(sender: NSStatusBarButton) {
    let event = NSApp.currentEvent!

    if event.type == NSEvent.EventType.rightMouseUp {
        print("Right click")
    } else {
        print("Left click")
    }
}

更长的帖子可在https://samoylov.eu/2016/09/14/handling-left-and-right-click-at-nsstatusbar-with-swift-3/上找到

为此，您可以使用statusItem按钮属性。

let statusItem = NSStatusBar.systemStatusBar().statusItemWithLength(-1)  
    let statusButton = statusItem!.button!
    statusButton?.target = self // or wherever you implement the action method
    statusButton?.action = "statusItemClicked:" // give any name you want
    statusButton?.sendActionOn(Int((NSEventMask.LeftMouseUpMask | NSEventMask.RightMouseUpMask).rawValue)) // what type of action to observe

然后实现action函数，在上面的代码中，我将其命名为“statusItemClicked”

func statusItemClicked(sender: NSStatusBarButton!){
    var event:NSEvent! = NSApp.currentEvent!
    if (event.type == NSEventType.RightMouseUp) {
        statusItem?.menu = myMenu //set the menu
        statusItem?.popUpStatusItemMenu(myMenu)// show the menu 
    }
    else{
        // call your function here
    }
}

在雨燕5中，
我是这样工作的。我能够从上面的答案中检测出它是右键单击还是左键单击。
但是，右键单击后，只能始终显示NSMenu。
然后，将statusItem.button?.performClick(nil)和statusItem?.menu = nil相加
您可以添加statusItem?.popUpMenu(menu)，但它在macOS 10.14中会贬值。（但它运行得很好。）
最后，如果左键单击，它会运行一个函数。如果右键单击，它会运行像退出这样的菜单项。
感谢之前回答的人！

class AppDelegate: NSObject, NSApplicationDelegate {
  func applicationDidFinishedLaunching(_ notification: Notification) {
    // .....
    // .....

    if let button = statusItem?.button {
        button.image = NSImage(named: "iconImage")
        button.action = #selector(self.statusBarButtonClicked(_:))
        button.sendAction(on: [.leftMouseUp, .rightMouseUp])
    }
    // Add Menu Item for NSMenu
    menu.addItem(NSMenuItem(title: "Quit", action: #selector(NSApplication.terminate(_:)), keyEquivalent: "q"))
  }
  @objc func statusBarButtonClicked(_ sender: NSStatusBarButton) {
    let event = NSApp.currentEvent!
    if event.type == NSEvent.EventType.rightMouseUp {
      print("Right Click")
      statusItem?.menu = menu
      statusItem?.button?.performClick(nil)
      // statusItem?.popUpMenu(menu)
      statusItem?.menu = nil
    } else {
      print("Left Click")
      togglePopover(sender)
    }
  }
}