swift2 Swift：如何获得某个字符集后的所有内容

yqhsw0fo 于 2022-11-06 发布在 Swift

关注(0)|答案(4)|浏览(208)

给定以下字符串：

var snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"

如何提取“Phone：“之后的所有内容
在这种情况下我想

phone = 123.456.7891

我试过这个：

if let range = snippet.rangeOfString("Phone:") {

        let phone = snippet.substringToIndex(range.startIndex)
        print(phone) // prints 1111 West Main Street Beverly Hills, CA 90210
    }

但这打印之前的一切，我需要之后的一切。

swift2

来源：https://stackoverflow.com/questions/34073610/swift-how-to-get-everything-after-a-certain-set-of-characters

4条答案

按热度按时间

9w11ddsr1#

在Swift 4中，使用upperBound和下标运算符和开值域：

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"

if let range = snippet.range(of: "Phone: ") {
    let phone = snippet[range.upperBound...]
    print(phone) // prints "123.456.7891"
}

或者考虑修剪空白：

if let range = snippet.range(of: "Phone:") {
    let phone = snippet[range.upperBound...].trimmingCharacters(in: .whitespaces)
    print(phone) // prints "123.456.7891"
}

顺便说一下，如果您试图同时获取这两个值，正则表达式可以做到这一点：

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"
let regex = try! NSRegularExpression(pattern: #"^(.*?)\s*Phone:\s*(.*)$"#, options: .caseInsensitive)
if let match = regex.firstMatch(in: snippet, range: NSRange(snippet.startIndex..., in: snippet)) {
    let address = snippet[Range(match.range(at: 1), in: snippet)!]
    let phone = snippet[Range(match.range(at: 2), in: snippet)!]
}

有关Swift的早期版本，请参见previous revision of this answer。

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jum4pzuy2#

对于一个非常基本的方法，假设您可以保证字符串的格式，您可以使用.components(separatedBy: "Phone: ")，因此索引0之前和索引1之后的任何内容

var snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"
let phoneNumber = snippet.components(separatedBy: "Phone: ")[1]
print(phoneNumber)
//prints everything that appears after "Phone: " in your snippet string
//"123.456.7891"

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ufj5ltwl3#

检查一下这个

let delimiter = ", "
let newstr = "Hello, playground"
let token = newstr.components(separatedBy: delimiter)
let first = token[0]
let last = token[1]
print("\(first) \(last)")

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lsmepo6l4#

只需使用func substringFromIndex，但将索引增加"Phone:"的长度

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