swift2 如何在swift中从NSTextCheckingResult对象中找到子字符串？

oiopk7p5 于 2022-11-06 发布在 Swift

关注(0)|答案(3)|浏览(247)

我想知道如何从NSTextCheckingResult对象中找到子字符串。到目前为止，我已经尝试过了：

import Foundation {
    let input = "My name Swift is Taylor Swift "
    let regex = try NSRegularExpression(pattern: "Swift|Taylor", options:NSRegularExpressionOptions.CaseInsensitive) 
    let matches = regex.matchesInString(input, options: [], range:   NSMakeRange(0, input.characters.count))
    for match in matches {
    // what will be the code here?
}

swift2

来源：https://stackoverflow.com/questions/36075857/how-can-i-find-the-substrings-from-the-nstextcheckingresult-objects-in-swift

3条答案

按热度按时间

xienkqul1#

试试看：

import Foundation

let input = "My name Swift is Taylor Swift "// the input string where we will find for the pattern
let nsString = input as NSString

let regex = try NSRegularExpression(pattern: "Swift|Taylor", options: NSRegularExpressionOptions.CaseInsensitive)
//matches will store the all range objects in form of NSTextCheckingResult 
let matches = regex.matchesInString(input, options: [], range: NSMakeRange(0, input.characters.count)) as Array<NSTextCheckingResult>

for match in matches {
    // what will be the code
    let range = match.range
    let matchString = nsString.substringWithRange(match.range) as String
    print("match is \(range) \(matchString)")
}

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ymdaylpp2#

下面是Swift 3的代码。它返回一个String数组

results.map {
        String(text[Range($0.range, in: text)!])
    }

所以总体的例子可能是这样的：

let regex = try NSRegularExpression(pattern: regex)
    let results = regex.matches(in: text,
                                range: NSRange(text.startIndex..., in: text))
    return results.map {
        String(text[Range($0.range, in: text)!])
    }

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wqsoz72f3#

你可以把这段代码放在for循环中，str将包含匹配的字符串。
let range = match.range let str = (input as NSString).substringWithRange(range)个

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