根据您的数组

var numbers = [1, 2, 3, 4]

和要删除的Set个索引

let indexesToRemove: Set = [1, 3]

您要删除值“2”和“4”。
就写

numbers = numbers
    .enumerated()
    .filter { !indexesToRemove.contains($0.offset) }
    .map { $0.element }

结果

print(numbers) // [1, 3]

很简单，从最后删除项目.
首先删除3，然后删除1

**Swift 3：**使用swift闭包执行相同的操作。

如果您的数组类似于

var numbers = [0, 1, 2, 3, 4, 5]

和索引

let indexesToBeRemoved: Set = [2, 4]

numbers = numbers
    .enumerated()
    .filter { !indexesToRemove.contains($0.offset) }
    .map { $0.element }
and result

打印（数字）// [0，1，3，5]

**Swift 3：**这是JSON对象（字典）的相同操作

var arrayString = [
    [ "char" : "Z" ],
    [ "char" : "Y" ],
    [ "char" : "X" ],
    [ "char" : "W" ],
    [ "char" : "V" ],
    [ "char" : "U" ],
    [ "char" : "T" ],
    [ "char" : "S" ]
]

let arrayIndex = [2, 3, 5]

arrayString = arrayString.enumerated()
    .filter { !arrayIndex.contains($0.0 + 1) }
    .map { $0.1 }

print(arrayString)

[[“字符”：“Z”]，[“字符”：“W”]，[“字符”：“U”]，[“名称”：“T”]，[“名称”：“S”]]