我可以使用GsonConverterFactory将JSON转换为HashMap吗？

我使用Retrofit库获得了以下数据：

[
  {
    "countryId": "1472",
    "countryName": "{"ar": "ألمانيا", "default": "Germany"}",
    "image": "a304035c3dcb42cd990bb69b2f03e31f.png"
  },
  {
    "countryId": "1473",
    "countryName": "{"ar": "إيطاليا", "default": "Italy"}",
    "image": "5b3ae479ada846e98309ed978c2707b5.png"
  },
  {
    "countryId": "1474",
    "countryName": "{"ar": "هولندا", "default": "Netherlands"}",
    "image": "d810f9ab22434b4da08b838e72add09d.png"
  },
  {
    "countryId": "1475",
    "countryName": "{"ar": "بولندا", "default": "Poland"}",
    "image": "d8c4de2a11ca45759089fec204af9659.png"
  },
  {
    "countryId": "1476",
    "countryName": "{"ar": "رومانيا", "default": "Romania"}",
    "image": "47efdea8456244a5b9aae7132fca7418.png"
  },
  {
    "countryId": "1477",
    "countryName": "{"ar": "روسيا", "default": "Russia"}",
    "image": "7163f60a1c494e1b9f782edd3ecabd31.png"
  },
  {
    "countryId": "1478",
    "countryName": "{"ar": "إسبانيا", "default": "Spain"}",
    "image": "52fe49f594074b078fd5d8c9625018ee.png"
  },
  {
    "countryId": "1479",
    "countryName": "{"ar": "اوكرانيا", "default": "Ukraine"}",
    "image": "28581f7e4f324d938e0b109f7ee9203e.png"
  },
  {
    "countryId": "1480",
    "countryName": "{"ar": "المملكة المتحدة", "default": "United Kingdom"}",
    "image": "e7a87ff0caa241559f6c2559cc8606c3.png"
  },
  {
    "countryId": "2147483647",
    "countryName": "{"ar": "فرنسا", "default": "France"}",
    "image": "3830917201c74fc9b6b4ed0ddfdd4866.png"
  }
]

下面是获取数据的代码：

Retrofit retrofit = new Retrofit.Builder().baseUrl(Constants.baseURL).addConverterFactory(GsonConverterFactory.create()).build();
TestInterface testInterface = retrofit.create(TestInterface.class);
testInterface.getCountries().enqueue(new Callback < List < CountriesModel >> () {
    @Override
    public void onResponse(@NonNull Call < List < CountriesModel >> call, @NonNull Response < List < CountriesModel >> response) {
        if (response.body() == null)
            return;
        for (CountriesModel item: response.body()) {
            Chip chip = new Chip(requireActivity());
            chip.setText(item.getCountryName());
            fragmentSelectCountryBinding.fragmentSelectCountryChipGroup281.addView(chip);
        }
    }

    @Override
    public void onFailure(@NonNull Call < List < CountriesModel >> call, @NonNull Throwable t) {
        Log.w(Tag, "Failed - " + t.getMessage());
    }
});

测试界面

public interface TestInterface {

    @GET("FetchCountries.php")
    Call<List<CountriesModel>> getCountries();

}

国家/地区模型类

public class CountriesModel {

    @SerializedName("countryId")
    private long countryId;

    @SerializedName("countryName")
    private String countryName;

    @SerializedName("image")
    private String image;

    public long getCountryId() {
        return countryId;
    }

    public String getCountryName() {
        return countryName;
    }

    public String getImage() {
        return image;
    }

}

MySQL中的列

国家/地区名称在芯片中显示如下：{"ar": "ألمانيا", "default": "Germany"}, {"ar": "إيطاليا", "default": "Italy"}, {"ar": "هولندا", "default": "Netherlands"}, etc...
国家名里面的JSON。我可以把它存储在HashMap中，然后根据下面的键得到值吗？
chip.setText(item.getCountryName().get("default"));个
我可以使用GsonConverterFactory执行类似的操作吗？
This answer接近我想要的，但我想在同一个模型中做那件事，而不需要创建两个模型。

也许你可以，但我不确定你是否应该。你的问题似乎是国家名称实际上是“内部”JSON。我猜它实际上是如下所示的转义，否则它将无法解析：

[
 {
    "countryId": "1476",
    "countryName": "{\"ar\": \"رومانيا\", \"default\": \"Romania\"}",
    "image": "47efdea8456244a5b9aae7132fca7418.png"
  }
]

可以只为 countryName 创建一个自己的类，并创建一个自定义反序列化器来处理这个“内部”JSON。请参见下面的示例（不需要静态内部类，但我这样做是为了简洁）：

@Getter @Setter
public class CountriesModel {
    private long countryId;

    // define representation for complex name
    @Getter @Setter
    public static class CountryName {

        // define a custom deserializer for "inner" JSON
        public static class CountryNameDeserializer
                implements JsonDeserializer<CountryName> {
            private final Gson gson = new Gson();
            @Override
            public CountryName deserialize(JsonElement json, Type typeOfT,
                                           JsonDeserializationContext context)
                    throws JsonParseException {

                // gets the field as string and parses it again as a CountryName object
                return gson.fromJson(json.getAsString(), CountryName.class);
            }
        }
        private String ar;

        // default is a reserved word
        @SerializedName("default")
        private String defaultName;
    }

    // Use the adapter
    @JsonAdapter(CountryNameDeserializer.class)
    private CountryName countryName;
    private String image;
}

现在就好比：

someCountriesModel.getCountryName().getDefaultName();

我可以使用GsonConverterFactory将JSON转换为HashMap吗？

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