{ "ChangeRequests": [ {} ]}
{
"ChangeRequests": [
{}
]
}
使用Gson从JSON数组中删除空模型。因为它在列表中创建一个模型，所以使用Gson将模型中的所有值都设置为空
data class TestRequest(@SerializedName("ChangeRequests")val changeRequests: List<ChangeRequest>
data class TestRequest(
@SerializedName("ChangeRequests")
val changeRequests: List<ChangeRequest>
）
val result = Gson().fromJson(jsonString,TestRequest::class.java)
ergxz8rk1#
简单代码：对我很有效！
Type type = new TypeToken<Map<String, Object>>() {}.getType();Map<String, Object> data = new Gson().fromJson(jsonString, type);for (Iterator<Map.Entry<String, Object>> it = data.entrySet().iterator(); it.hasNext();) {Map.Entry<String, Object> entry = it.next();if (entry.getValue() == null) { it.remove();} else if (entry.getValue().getClass().equals(ArrayList.class)) { if (((ArrayList<?>) entry.getValue()).size() == 0) { it.remove(); } }}String json = new GsonBuilder().setPrettyPrinting().create().toJson(data);System.out.println(json);
Type type = new TypeToken<Map<String, Object>>() {}.getType();
Map<String, Object> data = new Gson().fromJson(jsonString, type);
for (Iterator<Map.Entry<String, Object>> it = data.entrySet().iterator();
it.hasNext();) {
Map.Entry<String, Object> entry = it.next();
if (entry.getValue() == null) {
it.remove();
} else if (entry.getValue().getClass().equals(ArrayList.class)) {
if (((ArrayList<?>) entry.getValue()).size() == 0) {
String json = new GsonBuilder().setPrettyPrinting().create().toJson(data);
System.out.println(json);
1条答案
按热度按时间ergxz8rk1#
简单代码：对我很有效！