使用GSON fromJson方法将JSON数组转换为对象

frebpwbc  于 2022-11-06  发布在  其他
关注(0)|答案(4)|浏览(177)

我有一个WCFWebservice,其中发送了一个数据模型,我通过JSon(通过实体框架)在Android中获得了这个数据模型,无论如何,我都可以通过此代码成功地获得JSON,并将所有JSON对象存储在AsyncTas类的JSONArray中,以及:

public class Consume extends AsyncTask<Void, Void, Void> {

            InputStream inputStream = null;
            String result = "";
            private ArrayList<Contact> contacts = new ArrayList<Contact>();

        @Override
            protected Void doInBackground(Void... params) {
                String URL = "http://x.x.x.x/MyWCF/Service1.svc/rest/getContact";
                ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();
                try {
                    HttpClient httpClient = new DefaultHttpClient();
                    HttpPost post = new HttpPost(URL);
                    post.setEntity(new UrlEncodedFormEntity(param));
                    HttpResponse httpResponse = httpClient.execute(post);
                    HttpEntity httpEntity = httpResponse.getEntity();
                    //post.setHeader("content-type", "application/json");
                    inputStream = httpEntity.getContent();

                } catch (UnsupportedEncodingException e1) {
                    Log.e("UnsupportedEncoding", e1.toString());
                    e1.printStackTrace();
                } catch (ClientProtocolException e2) {
                    Log.e("ClientProtocolException", e2.toString());
                    e2.printStackTrace();
                } catch (IllegalStateException e3) {
                    Log.e("IllegalStateException", e3.toString());
                    e3.printStackTrace();
                } catch (IOException e4) {
                    Log.e("IOException", e4.toString());
                    e4.printStackTrace();
                }
                try {
                    BufferedReader bReader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"), 8);

                    StringBuilder sBuilder = new StringBuilder();

                    String line = null;
                    while ((line = bReader.readLine()) != null) {
                        sBuilder.append(line + "\n");
                    }
                    inputStream.close();
                    result = sBuilder.toString();
                } catch (Exception e) {
                    Log.e("StringBuilding", "Error converting result " + e.toString());
                }
                return null;
            }

            @Override
            protected void onPostExecute(Void aVoid) {
                super.onPostExecute(aVoid);
                try {
                    JSONObject object = new JSONObject(result);
                    JSONArray jArray = object.getJSONArray("getContactResult");  //here i create the JsonArray of all JsonObjects

//Here  is the solutions, We make a list of out Contact and make it as down

            List<Contact> contacts;
           Type listType = new TypeToken<List<Contact>>() {
           }.getType();
           contacts= new Gson().fromJson(String.valueOf(jArray), listType);

//And here solution is ended !

               } catch (JSONException e) {
                    e.printStackTrace();
                }
            }

我在android中创建了一个联系人class,代码如下:

public class Contact {

 @SerializedName("name")
    private String name;

        @SerializedName("lastName")
        private String lastName;

        @SerializedName("phoneNumber")
        private String phoneNumber;

        @SerializedName("latitude")
        private String latitude;

        @SerializedName("longitude")
        private String longitude;

        public void setName(String name) {
            this.name = name;
        }

        public String getName() {
            return name;
        }

        public void setLastName(String lastName) {
            this.lastName = lastName;
        }

        public String getLastName() {
            return lastName;
        }

        public void setPhoneNumber(String phoneNumber) {
            this.phoneNumber = phoneNumber;
        }

        public String getPhoneNumber() {
            return phoneNumber;
        }

        public void setLatitude(String latitude) {
            this.latitude = latitude;
        }

        public String getLatitude() {
            return latitude;
        }

    public void setLongitude(String longitude) {
        this.longitude = longitude;
    }

    public String getLongitude() {
        return longitude;
    }
}

我用老方法解析这个JSONArray!用这个方法:

ArrayList<Contact> setFields(JSONArray jsonArray) {
        ArrayList<Contact> contacts = new ArrayList<Contact>();
            for(int i=0; i<jsonArray.length(); i++) {
                try {
                    Contact contact = new Contact();
                    JSONObject object = (JSONObject) jsonArray.get(i);
                    contact.setName(object.getString("name"));
                    contact.setLastName(object.getString("lastName"));
                    contact.setPhoneNumber(object.getString("phoneNumber"));
                    contact.setLatitude(object.getString("latitude"));
                    contact.setLongitude(object.getString("longitude"));
                    contacts.add(contact);
                } catch (JSONException e) {
                    e.printStackTrace();
                }
            }
            return contacts;
        }

它工作,但我不想处理和解析JSONArray的这种老方法,并希望使用GSON代替,任何人都可以帮助我与这个例子?这里是我的JSONArrayJSON对象:

{
  "getContactResult": [
    {
      "id": 2041,
      "lastName": "xxxx",
      "latitude": xxx,
      "longitude": xxx,
      "name": "xxxx",
      "phoneNumber": "xxxx"
    }
  ]
}

谢谢

7xzttuei

7xzttuei1#

import com.google.gson.reflect.TypeToken;
import java.lang.reflect.Type;

List<Contact> contacts;    
Type listType = new TypeToken<List<Contact>>() {
                    }.getType();
 contacts= new Gson().fromJson(jsonArray, listType);

确保您的模型类与json参数和数据类型具有相同的名称。它会将jsonarray解析为java的类型List

qlzsbp2j

qlzsbp2j2#

这已经回答了,但我想分享一件事给你。简单和最好的方法
有一个插件Gson为android工作室。你需要安装。然后去CTRL +插入。你可以创建gson文件。输入一些名称为java文件。
点击该文件,然后粘贴json数据。点击确定。你可以看到你创建的json到gson格式。
谢谢,希望这对你有帮助。

xdnvmnnf

xdnvmnnf3#

Kotlin溶液

import com.google.gson.reflect.TypeToken;
import java.lang.reflect.Type;

val gson = Gson()
val type = object : TypeToken<List<Contact>>() {}.type
val listContact : KycProperties = gson.fromJson(jArray.toString(), type) as Contact

Java解决方案

import com.google.gson.reflect.TypeToken;
import java.lang.reflect.Type;

List<Contact> listContact;    
Type type = new TypeToken<List<Contact>>() {
                }.getType();
listContact= new Gson().fromJson(jsonArray.toString(), type);
5us2dqdw

5us2dqdw4#

将Gson和JSON结合起来(一种不同的方法),对于新手来说很简单。

ArrayList<Sukh>sukhs new ArrayList<>();
       Gson gson = new Gson();
       try {
           JSONArray jsonArray = new JSONArray(fullJsonArrayString);
           for (int i = 0; i < jsonArray.length(); i++) {
               JSONObject jsonObject=jsonArray.getJSONObject(i);
               Sukh sukhObject = gson.fromJson(jsonObject.toString(), Sukh.class);
               sukhs.add(sukhObject);
           }
       } catch (JSONException e) {
           e.printStackTrace();
       }

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